Y^2 + 4y - 32 = 0
y^2 - 4y + 8y - 32 = 0
y(y - 4) + 8(y - 4) = 0
(y + 8)(y - 4) = 0
y + 8 = 0 or y - 4 = 0
y = -8 or y = 4.
Answer:
24
Step-by-step explanation:
simpley look up the lcm of 6 and 8 and youll get the answer... very simple
300,000+70,000+3,000+600+90+8
The manager already hired 9 people. Let 
be the number of people he still can hire. Since these people will add to the 9 he already hired, when the hiring campaign will be over he will have hired 
people. We know that he can't hire more than 14 people, so the number of people hired must be less than or equal to 14:
If we subtract 9 from both sides, we have
so, the manager can hire at most 5 other people
