we have 25 individuals that are randomly selected out of 100 shoppers leaving a local bedding store, and we know that each of the shoppers has the SAME probability of answering yes to having made a purchase, so we can assume that the probability that a person or a shopper made a purchase is 1 / 12.
Also we know that we selected 25 individuals, so there are 25 shoppers that can say yes, that means our sample size N is 25.
and you want to know the probability that exactly 4 of the 25 shoppers made a purchase
this is a binomial distribution because we can see that we have a sample size n = 25, we have a proportion of success, 1/2to say yes to having made a purchase and we can say that each shopper is independently from the other shoppers.
So the binomial equation is given by: (check the attached image)
so we know that we want P(X=4) because we want to know exactly 4 out of 25.
so n is 25, p is 1/2 and x is 4 so substituting the values into the equation we will get:
P(X=4) = 25C4 * (1/2)^4 * (1 - 1/2)^(25-4)
P(X=4) = 12650 * 0.0625 * 0.000000476
P(X=4) = 0.000377
the probability that exactly 4 of the 25 shoppers made a purchase is....0.00010243
Answer: (6, 5)
Step-by-step explanation: (2+4,-3-2) = (6, -5)
After reflection on x - axis, the y value changes the sign from negative to positive (to the opposite) : (6,5)
Answer: 5 * x * a
Step-by-step explanation:
It’s algebra
I am somehow confused with the given matrix. Because usually, when the system of equations is given as:
ax + by = c
dx + ey = f
the matrix would be written in this manner:
![\left[\begin{array}{ccc}a&b&c\\d&e&f\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%26c%5C%5Cd%26e%26f%5Cend%7Barray%7D%5Cright%5D%20)
Let me just assume that the arrangement of the given corresponds to this system of equations:
4x + 8y = 0
2x + 5y = 6
So you write it as
![\left[\begin{array}{ccc}4&8&0\\2&5&6\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%268%260%5C%5C2%265%266%5Cend%7Barray%7D%5Cright%5D%20)
In order to solve this, the matrix should look like this where x and y are the answers
![\left[\begin{array}{ccc}1&0&x\\0&1&y\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26x%5C%5C0%261%26y%5Cend%7Barray%7D%5Cright%5D%20)
So, the first thing to do is apply this pattern: Row 2 = Row 1 - 2*Row 2. The result will be
![\left[\begin{array}{ccc}4&8&0\\0&-2&-12\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%268%260%5C%5C0%26-2%26-12%5Cend%7Barray%7D%5Cright%5D%20)
Next, Row 1 = (Row 1/4) + R2:
![\left[\begin{array}{ccc}1&0&-12\\0&-2&-12\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26-12%5C%5C0%26-2%26-12%5Cend%7Barray%7D%5Cright%5D%20)
Lastly, Row 2 = Row 2 / -2:
Thus, the answer is x=-12 and y=6.
Answer:
the answer is C
Step-by-step explanation: