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maxonik [38]
3 years ago
14

A small-business owner must hire seasonal workers as the need arises. The following list shows the number of employees hired mon

thly for a 5-month period. 4, 13, 5, 6, 7 Calculate the standard deviation of the data. Round the answer to the nearest hundredth. 35.63 12.36 7 3.16
Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0
So you need to find the mean (average) of the 5 numbers. so add them together and divide by 5, since there are five numbers. your answer should be 7
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247 + 794 is the same as<br> ? + 800
Dmitry [639]
241 + 800 = 1041
247 + 794 = 1041
5 0
3 years ago
Read 2 more answers
Work out 6/5 of 200 and show working out
katrin [286]

Answer:

240.

Step-by-step explanation:

200 * 6/5

= 1200/5

= 240

5 0
3 years ago
A red candle is 8 inches tall and burns at a rate of 7/10 inch per hour. a blue cans is 6 inches tall and burns at a rate of 1/5
Galina-37 [17]
Let t = number of hours

The first candle starts at 8 inches.
It burns at 7/10 inch per hour, so in t hours it burns (7/10)t inches.
After t hours, its length is 8 - (7/10)t

The second candle starts at 6 inches.
It burns at 1/5 inch per hour, so in t hours it burns (1/5)t inches.
After t hours, its length is 6 - (1/5)t

You want the lengths to be equal, so the equation is

8 - (7/10)t = 6 - (1/5)t
4 0
3 years ago
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0
3 years ago
The system of equations below represents p, the number of photo files, and v, the number of video files Helena uploaded to an on
ss7ja [257]
P + v = 650....p = 650 - v
4p + 9v = 2925

4(650 - v) + 9v = 2925
2600 - 4v + 9v = 2925
-4v + 9v = 2925 - 2600
5v = 325
v = 325/5
v = 65.....video files

p + v = 650
p + 65 = 650
p = 650 - 65
p = 585....photo files

answer : Helena uploaded 9 times as many photo files as video files
               65 * 9 = 585
5 0
3 years ago
Read 2 more answers
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