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ikadub [295]
3 years ago
14

The store sale 85% off only today. Ella planned to buy these skates anyway, and so she bought them immediately.

Mathematics
1 answer:
daser333 [38]3 years ago
3 0
Let x be the original price. Then the discounted price is
                                         discount = x(1 - 0.85)
The discounted price is $18.00. Therefore
                                         18.00 = x(0.15)
                                                 x = 18.00 / 0.15
                                                 x = $120.00
The amount she saved is $120.00 - $18.00 = $102.00

The answer to this question is that Ella saved $102.00.
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Hi what is the answerr??
inna [77]

Given:

The rule of input and output function is:

25-g

To find:

The answer if we put 19.

Solution:

Consider the input and output function is:

f(g)=25-g

Substitute g=19, we get

f(19)=25-19

f(19)=6

Therefore, the required answer is 6.

7 0
2 years ago
Use the compass and ruler to construct the bisector of the angle given below.
soldier1979 [14.2K]
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8 0
2 years ago
1/6divid by 5 and I need help for my sis that is 2
elixir [45]

Answer:

The answer is 5/6

Step-by-step explanation:

1/6 x 5 is 5/6. You can do 1 x 5 which is 5. You don't need to multiply anything else. The answer is 5/6

6 0
3 years ago
What is the value of 1^2−2x−3y5for x = 2 and y = –4?
NikAS [45]
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5 0
2 years ago
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
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