Please help!!! My math teacher won’t

I WILL GIVE BRAINLIEST!

Nesterboy [21]

Answer:

$6

Step-by-step explanation:

So we get 5 hrs.

1____2____3____4____5

$2 + $1 + $1 + $1 + $1 = $6

4 0

3 years ago

Compute the exact interest on $5,870 at 12% if the money is borrowed from June to December of the same year.

yawa3891 [41]

Answer:

The exact interest on $5,870 at 12% is $410.9

Step-by-step explanation:

From the information provided we know that

Principal amount: $5,870

Interest rate: 12% -> 0.12

Time: 7 months (From June to December)

When you know the principal amount, the rate, and the time, the amount of interest can be calculated by using the formula:

$I=P\cdot r\cdot t$

where P is principal, r is the rate of interest and t is the time in years.

We need to convert the 7 months into 1 year.

$7 \>months \cdot \frac{1 year}{12 months} = \frac{7}{12} year$

Now we can use the above formula

$I=P\cdot r\cdot t=5870\cdot 0.12 \cdot \frac{7}{12} \\I = 0.12\cdot \frac{7\cdot \:5870}{12}\\I = 0.12\cdot \frac{20545}{6}\\I = \frac{2465.4}{6}\\I = 410.9$

Therefore the exact interest on $5,870 at 12% is $410.9

7 0

3 years ago

PLEASE HELP! ASAP!! 25 POINTS

brilliants [131]

Answer:

25 Points

Step-by-step explanation:

That the only number

6 0

3 years ago

PLEASE HELP!!! 15 PTS!!

kherson [118]

Answer:

$\large\boxed{C.\ (2,\ -45^o)}$

Step-by-step explanation:

Regular coordinates (x, y)

Polar coordinates (r, φ)

$r=\sqrt{x^2+y^2}\\\\\psi=\arctan\frac{y}{x}$

We have the point

$(\sqrt2,\ -\sqrt2)$

Substitute:

$r=\sqrt{(\sqrt2)^2+(-\sqrt2)^2}=\sqrt{2+2}=\sqrt4=2\\\\\psi=\arctan\left(\frac{-\sqrt2}{\sqrt2}\right)=\arctan(-1)=-45^o$

6 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago