Answer:
I don't know it to be honest but I'm curious now
Answer:
We conclude that the actual average cost per workbook is higher than $27.50.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = $27.50
Sample mean, = $28.90
Sample size, n = 44
Alpha, α = 0.05
Population standard deviation, σ = $5.00
First, we design the null and the alternate hypothesis
We use one-tailed z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We reject the null hypothesis and accept the alternate hypothesis.
Thus, we conclude that the actual average cost per workbook is higher than $27.50.
Answer:
360
Step-by-step explanation:
If we originally have 9 red cubes, 5 green cubes, and 11 blue cubes, if we add these, we have to:
9 + 5 + 11 = 25
This means that the probability of network cubes of 9/25, now without 1000 pulls, would be:
1000 * 9/25 = 360
That means that about 360 red cubes are expected, probably
5√7 × 3√14 = 5 × 3√(7 × 14)
= 15√98
= 105√2
Answer:
For example, the years 1600, 2000, and 2400 are century leap years since those numbers are divisible by 400, while 1700, 1800, 1900, 2100, 2200, and 2300 are common years despite being divisible by 4.
Step-by-step explanation: