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yanalaym [24]
3 years ago
15

If $22,000 is deposited in an account paying 3.85% interest compounded continuously, use the continuously compounded interest fo

rmula , A=Pe^rt, to find the balance in the account after 11 years.
A. $1,519,356.93
B. $33,600.60
C. $33,416.25
D. $25,416.25
Mathematics
2 answers:
Natalija [7]3 years ago
6 0

Answer:

B

Step-by-step explanation:

In the equation for interest compounding continuously, the A stands for the amount after the compounding is done, the P is the initial amount invested, the e is Euler's number, the r is the rate in decimal form, and the t is the time in years that the money is invested.  Setting up our equation with the given values looks like this:

A=22,000e^{(.0385)(11)}

Multiply the rate with the time to simplify a bit to

A=22,000e^{.4235}

Raise e to the power of .4235 on your calculator (hit 2nd then the ln button to get your e) and get

A=22,000(1.527297754)

Multiply out to get $33600.55, but rounding up gives you B as your answer.

mixer [17]3 years ago
6 0

Answer:

B is the answer

Step-by-step explanation:

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Plzz help me <br><br> Solve -24 = 6x. Show your work.
ZanzabumX [31]

Answer:

x = -4

Step-by-step explanation:

-24 = 6x

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Switch sides:

6x = -24

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Divide both sides by 6:

6x/6 = -24/6

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Simplify:

X = -4

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B4%7D%20-%20%20%5Cfrac%7B3%7D%7B8%7Dy%20%3D%203%20%5C%5C%20" id="TexFormula
MariettaO [177]

Answer:

(6, - 4 )

Step-by-step explanation:

Given the 2 equations

\frac{x}{4} - \frac{3}{8} y = 3 → (1)

\frac{5}{3} x - \frac{y}{2} = 12 → (2)

Multiply (1) by 8 and (2) by 6 to clear the fractions

2x - 3y = 24 → (3)

10x - 3y = 72 → (4)

Rearrange (3) expressing - 3y in terms of x by subtracting 2x from both sides

- 3y = 24 - 2x

Substitute 3y = 24 - 2x into (4)

10x + 24 - 2x = 72, that is

8x + 24 = 72 ( subtract 24 from both sides )

8x = 48 ( divide both sides by 8 )

x = 6

Substitute x = 6 in either (3) or (4) and solve for y

Substituting in (3)

2(6) - 3y = 24

12 - 3y = 24 ( subtract 12 from both sides )

- 3y = 12 ( divide both sides by - 3 )

y = - 4

Solution is (6, - 4 )

3 0
3 years ago
Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.
gavmur [86]

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

Learn more details about integer here:

brainly.com/question/15276410

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4 0
1 year ago
Which expression is equivalent to 3\tfrac{1}{3}-8\tfrac{2}{3}3
Sholpan [36]

Answer:

and yeah ikr I don't understand why

3 0
3 years ago
Javier simplified the expression below. Find and describe the three mistakes he made.
OverLord2011 [107]
( \dfrac{20x}{5x^8})^-^3 

<span>Take out the constants
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Use the rule : \frac{{x}^{a}}{{x}^{b}}={x}^{a-b}&#10; 

(4x^1^-^8)^-^3 

(4x^-^7)^-^3 

Use the n<span>egative power rule : </span>{x}^{-a}=\frac{1}{{x}^{a}}&#10; 

\frac{1}{4(x^-^7)}^-^3 

\frac{1}{4^3(x^-^7)}^-^3 

\dfrac{1}{64x^-^2^1} 

\dfrac{1}{64* \dfrac{1}{x^2^1}} 

\dfrac{1}{64 \dfrac{}{x^2^1}} 

= \dfrac{x^2^1}{64}
6 0
3 years ago
Read 2 more answers
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