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svlad2 [7]
3 years ago
14

Lisa solved 40 math fact problems in 2 1/2 minutes.

Mathematics
2 answers:
vesna_86 [32]3 years ago
8 0

Answer:

Her unit rate remained the same

Step-by-step explanation:

80 is twice as much as 40. 5 minutes is twice as long as 2 1/2 minutes. Her unit rate never changed.

allochka39001 [22]3 years ago
8 0

Answer:

her unit rate remained the same

Step-by-step explanation:

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27 square units is the answer
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muminat

Answer lit

Step-by-step explanation:

6 0
3 years ago
The table lists the number of male and female students at Lakeside High school.
AysviL [449]

Answer:

C) 161/163

Step-by-step explanation:

First, you add up all the students for both genders.

Female- 193+ 214 +197+ 201 = 805

Male- 216+ 207+ 198 + 194 = 815

That gives you a fraction on 805/815 which you simplify to 161/163

So your answer would be C, 161/163 :)

4 0
3 years ago
Convert the equation to the standard form for a hyperbola 4x^2-25y^2-8x+50y-121=0
S_A_V [24]
We have that
4x²-25y²<span>-8x+50y-121=0

</span><span>Group terms that contain the same variable, and move the constant to the opposite side of the equation
</span>(4x²-8x)+(-25y²+50y)=121

Factor the leading coefficient of each expression
4(x²-2x)-25(y²-2y)=121

Complete the square twice. Remember to balance the equation by adding the same constants to each side.
4(x²-2x+1)²-25(y²-2y+1)²=121+4-25

Rewrite as perfect squares
4(x-1)²-25(y-1)²=100

<span>Divide both sides by the constant term to place the equation in standard form</span>
(4/100)(x-1)²-(25/100)(y-1)²=100/100
(1/25)(x-1)²-(1/4)(y-1)²=1

[(x-1)²]/25-[(y-1)²]/4=1

the answer is
[(x-1)²]/25-[(y-1)²]/4=1


7 0
4 years ago
A line passes through (-9,-5) and (2,-4)
zlopas [31]

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-9, -5) and (2, -4). Substitute:

m=\dfrac{-4-(-5)}{2-(-9)}=\dfrac{1}{11}\\\\y-(-5)=\dfrac{1}{11}(x-(-9))\\\\\boxed{y+5=\dfrac{1}{11}(x+9)}\leftarrow\boxed{\text{point-slope form}}

The standard form of a line:

Ax+By=C

y+5=\dfrac{1}{11}(x+9)                <em>multiply both sides by 11</em>

11y+55=1(x+9)

11y+55=x+9     <em>subtract 9 from both sides</em>

11y+46=x      <em>subtract 11y from both sides</em>

46=x-11y

\boxed{x-11y=46}\leftarrow\boxed{\text{standard form}}

5 0
3 years ago
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