0.02375 uhhh write it out but there ya go
Count the number of cubes shaded so the 7x11 is 77 square units
hope that this helped you hon :)
Answer:
○ 
Step-by-step explanation:
3 → 13 − 16
![\displaystyle \frac{Number\:of\:desired\:[favourable]\:outcomes}{Total\:number\:of\:possible\:outcomes} \\ \\ \frac{3}{12} = \frac{1}{4} = 25\%](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BNumber%5C%3Aof%5C%3Adesired%5C%3A%5Bfavourable%5D%5C%3Aoutcomes%7D%7BTotal%5C%3Anumber%5C%3Aof%5C%3Apossible%5C%3Aoutcomes%7D%20%5C%5C%20%5C%5C%20%5Cfrac%7B3%7D%7B12%7D%20%3D%20%5Cfrac%7B1%7D%7B4%7D%20%3D%2025%5C%25)
I am joyous to assist you anytime.
Answer:
x = 2 cm
y = 2 cm
A(max) = 4 cm²
Step-by-step explanation: See Annex
The right isosceles triangle has two 45° angles and the right angle.
tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x
A(r) = x* y
Area of the rectangle as a function of x
A(x) = x * ( 4 - x ) A(x) = 4*x - x²
Tacking derivatives on both sides of the equation:
A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0
2*x = 4
x = 2 cm
And y = 4 - 2 = 2 cm
The rectangle of maximum area result to be a square of side 2 cm
A(max) = 2*2 = 4 cm²
To find out if A(x) has a maximum in the point x = 2
We get the second derivative
A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2
Answer:
x=-14
Step-by-step explanation:
-x-11^2+1
-x-11^3
-x^14
x=-14