So, the best way to solve this problem is by creating a equation for which we can substitute any number of days. For this problem that equation would be W=5+3(t-1)
W=number of words
T=time or number of days
-1= This is here because we are already accounting for the first day of school so we need to have 1 less day than the number of days they have been in school.
So in 20 days the students had received
5+3(19) or 62words.
Answer: 62 words
Answer:
Step-by-step explanation:
x^2 + 3x - 9 =0
By comparing with the equation ax^2+bx+c = 0,
we get,
a = 1, b=3, c = -9
we know the formula for x is,
x = (-b±√(b^2 - 4ac))/2a
x = (-3±√45)/2
x = (-3±3√5)/2
x = (-3+3√5)/2, (-3-3√5)/2
The lesser number is 30.
It took me about one minute to determine the two numbers by simple logic alone.
30 and 60 are the two numbers.
But, equation-wise, you have ...
30 x 2(30) = 1800
30 x 60 = 1800
Let's start by plugging in 1 for y. You get 7-2/6, which is 5/6. The other equation is 3-7/12, which equals -1/3. Now let's try 10. You get 7-2(10)/6, which is -13/6. The other equation is 3(10)-7/12, which is 23/12, and is larger!
1 is a value of y that could work!
Hope this helps!! :)
