Let: eq 1:2x+5y=-55
eq 2:y=3x+6
by substituting eq 2 in eq 1 we get,
2x+5(3x+6)=-55
2x+15x+30+55=0
17x + 85=0
x=-85/17
x=-5
By substituting x value in eq 2,
we have,
y=3(-5)+6=-15+6=-9
Invested amount (P0 = £6000.
Rate of interest (r) = 3.4% = 0.034.
We know compound interest formula
A = P(1+r)^t
We need work out the value of his investment per year.
So, we need to plug t=1 and plugging values of P and r in the formula above, we get
A = 6000(1+0.034)^1
A = 6000(1.034)
A = 6204.
<h3>Therefore, the value of his investment per year is £ 6204.</h3>
Now, we need to work out the value of his investment after 3 years.
So, we need to plug t=3.
A = 6000(1+0.034)^3
A = 6000(1.034)^3
1.034^3=1.105507304
A = 6000 × 1.105507304
A = 6633.04
<h3>Therefore, the value of his investment after 3 year is £ 6633.04.</h3>
Answer:
4 hours
Step-by-step explanation:
Write an equation
19 +1.5x < 15+2.75x
Subtarct 15 on both sides
4+1.5x<2.75x
subtract 1.5x on both sides
4< 1.25x
Divide 1.25 on each side
3.2<X
Since they on,y charge per hour so 4 hours
Answer: who made this question I think you need to round 250 to the nearest whole number I’m not sure.
Step-by-step explanation:
Answer is provided in the image attached.
