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Eduardwww [97]
3 years ago
14

HURRY ILL GIVE U BRAINLIEST!!! Find the area of each figure. Which do these belong in?

Mathematics
1 answer:
nordsb [41]3 years ago
4 0

Answer:

Area of rectangle PQRS is 14 square units.

Area of triangles UVW and EFG and square ABCD are 16 square units each.

Step-by-step explanation:

Let us find the area of each of the figures shown in the graph.

Area of rectangle PQRS is given as the product of PQ and QS.

From the graph,

Length of PQ = 7 units

Length of QS = 2 units

Now, area of rectangle PQRS = PQ\times QS=7\times 2=14 square units.

Now, area of square ABCD is given as the square of any of its side.

From the graph, AB = 4 units.

So, area of ABCD = AB^{2}=4^2=16 square units.

Area of triangle UVW is given as the half of the product of its base VW and height UW.

From the graph, UW = 4 units, VW = 8 units

Therefore, area of triangle UVW = \frac{1}{2}\times UW\times VW=\frac{1}{2}\times 4\times 8=16 square units.

For triangle EFG, EF = 4 units and FG = 8 units.

Area =  \frac{1}{2}\times EF\times FG=\frac{1}{2}\times 4\times 8=16 square units.

Area of rectangle PQRS is 14 square units. The remaining figures have areas each equal to 16 square units.

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ozzi

Your answer is x={-1, 11/3}

4 0
3 years ago
Am I right?
MariettaO [177]
Yes, your answer is right.
5 0
3 years ago
In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
3 years ago
Suppose a railroad rail is 3 kilometers and it expands on a hot day by 15 centimeters in length. Approximately how many meters w
earnstyle [38]

Answer:

Answer:  13.4 m

Step-by-step explanation:

For small angles, x, in radians,

tan(x) ≈ sin(x) = x

Use this to create an approximate diagram for the problem as shown in the figure below.

The actual deflected shape is parabolic, but it is approximated by an isosceles triangle with small equal angles.

The extend length is 3 km + 12 cm, which is 

3000 + 0.12 = 3000.12 m

Half of the extended length is 1500.06 m

Let h+  the rise of the center of the rail above ground.

From the Pythagorean theorem, obtain

h² + 1500² = 1500.6²

h² = 1500.06² - 1500² = 180.004

h = 13.4 m, which is about 0.9% of the original length.

Read more on Brainly.com - brainly.com/question/5596356#readmore

6 0
3 years ago
What are the factors of the quadratic function graphed below. Please show work , please help
dlinn [17]

Answer:

x and (x - 6)

Step-by-step explanation:

y = a(x - h)² + k

h = 3    k = -2

y = a (x - 3)² -2

For point (0 , 0) on the function

0 = a (0 - 3)² -2

0 = 9a - 2

a = 2/9

a (x - 3)² -2 = 2/9 (x² - 6x + 9) - 2 = 2/9 * x * (x - 6) + 2 - 2 = 2/9 * x * (x-6)

5 0
3 years ago
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