Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Add then I would divide it
Answer:C. 17,280
Step-by-step explanation:It this way because it cant be 3k obv or 6k. And it says 72% down not up so not d either :D
Answer:
63degrees
Step-by-step explanation:
Using the theorem which states that the measure of angle at the vertex is half the angle of its intercepted arc.
Given
angle of its intercepted arc = 126 degree
Required
angle at the vertex = x =<XYZ
According to the theorem;
x = 1/2(126)
x = 126/2
x = 63
Hence the measure of <XYZ is 63degrees
Answer:
Step-by-step explanation:
1/5* 1/4 * 1/3
I think it is the second one
one fifth
one fourth
one third
