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3 years ago

Can you help me with this page please??

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

5 0

Do you know the length and height of the field? If you do, all all the sides together (Height + Height + Length + Length) and you get the answer to Part A.

Part B:
Just do 120 times 5. Then, divide your answer by 6. The answer will be the time they need to run each lap in.

Part C:
Again, what is the length? When you know your length, divide it by 2. Your answer is the side length.

Hope that helped. :)

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A box of cereal contains 18 cups. Ben eats 2 1/4 cups every serving. How many servings can he eat?

g100num [7]

Ben can have 8 servings total!

Hope this helps! :)

4 0

4 years ago

Can someone help me plead

andrew-mc [135]

Answer:

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

Step-by-step explanation:

The following equations are given

a. 2 × 2× 2

b. 3 × 3 × 3 × 3

c. 4 × 4 × 4 × 5 × 5

d. 9 × 7 × 9 × 9 × 7 × 9

We need to find the index notation for the above equations

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

In this way it should be done

The same would be relevant

4 0

3 years ago

24% of what number is 12?

vladimir1956 [14]

To get that, you have to multiply the both numbers, which is 24*12=288

6 0

3 years ago

Read 2 more answers

Select a composite number to break into factors. Continue factoring until all factors are prime

Sladkaya [172]

Answer:

2*2 * 2*2 * 2*3

Step-by-step explanation:

96 =16 *6

Break these down, since neither 16 nor 6 are prime

= 4*4 * 2*3

4 in not prime, but 2 and 3 are prime

= 2*2 * 2*2 * 2*3

All of these are prime

7 0

3 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago