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AnnZ [28]
3 years ago
11

What is the slope of the line that contains these points? x| -7. -6. -5. -4 ----------------------------------------------------

--------- y| 21. 17. 13. 9
Mathematics
1 answer:
zepelin [54]3 years ago
6 0

Answer:

<h2>-4</h2>

Step-by-step explanation:

Given the line containing the points.

x | -7. -6. -5. -4

y | 21. 17. 13. 9

The slope of the line is expressed as m = Δy/Δx = y₂-y₁/x₂-x₁

Using the coordinates y (21, 17) and corresponding value of  x(-7, -6)

y₁ = 21, y₂ = 17 x₁ = -7, x₂ = -6

Substituting the values into the formula for calculating the slope, we have;

m = Δy/Δx = 17-21/-6-(-7)

m = -4/-6+7

m = -4/1

m = -4

<em>Hence the slope of the line that contains these points is -4</em>

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10.20*8= 81.60
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5 0
3 years ago
Find the domain of f/g
san4es73 [151]

Answer:

C. All real numbers except 3/4

Step-by-step explanation:

We are given

f(x)=3x^2+x^4+2

g(x)=4x-3

Firstly, we will find f/g

\frac{f}{g}=\frac{3x^2+x^4+2}{4x-3}

Domain:

We know that domain is all possible values of x for which any function is defined

so, we know that denominator of any function can not be zero

so, firstly we set denominator =0

and then we can solve for x

4x-3=0

Add both sides by 3

4x-3+3=0+3

4x=3

x=\frac{3}{4}

so, this function is defined for all values of x except at

x=\frac{3}{4}

Domain will be

All real numbers except 3/4

5 0
3 years ago
Write the equation in y intercept form
Vadim26 [7]

Answer:

y=-2x+4

Explanation:

Subtract 6x from both sides of the equation.

3y=12−6x

Divide each term by 3 and simplify.

Divide each term in 3y=12−6x by 3.

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3 years ago
4, 02, 03, α4, 28.<br> Find the common difference
hram777 [196]

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Step-by-step explanation:

GCF

5 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

n= 955 represent the sampel size slected

x = 812 number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

The confidence interval for the proportion  would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

And replacing into the confidence interval formula we got:

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

8 0
3 years ago
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