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Lorico [155]
3 years ago
7

Which Of the following functions will not have an axis of symmetry x=-1 when graphed

Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

The correct choice is A.

Step-by-step explanation:

The axis of symmetry of the function is given by

x=-\frac{b}{2a}

If the axis of symmetry is -1 then the relation between the 'a' and 'b' value for all the function that has an axis of symmetry to be -1, is

b=2a

A. y=4x^2-8x+1

We can see that

-8\ne 2(4)

hence this function does not have an AOS of x=-1

The correct choice is A.

B. y=x^2+2x-6

2\ne 2(1), hence this function has an axis of symmetry of x=-1.

C. y=3x^2+6x

6=2(3)

This also has AOS x=-1

D. y=-x^2-2x+3

-2=2(-1)

AOS is x=-1

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

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  • Functions
  • Function Notation
  • Terms/Coefficients
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}

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Derivative Notation

Basic Power Rule:

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Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \frac{3}{2x^2}<u />

\displaystyle \text{Point} \ (1, \frac{3}{2})

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Rewrite]:                                            \displaystyle y = \frac{3}{2}x^{-2}
  2. Basic Power Rule:                                                                                             \displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}
  3. Simplify:                                                                                                             \displaystyle y' = -3x^{-3}
  4. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle y' = \frac{-3}{x^3}

<u>Step 3: Solve</u>

  1. Substitute in coordinate [Derivative]:                                                              \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}
  2. Evaluate exponents:                                                                                         \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}
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Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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