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quester [9]
3 years ago
10

Please help me with 4 and 5

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

The answer to No. 4 is x = 12.

The answer to No. 5 is 160.

Step-by-step explanation:

(No. 4) The mean (average) is calculated by adding up all the numbers and then dividing by how many numbers there are.

In the first exercise, there are 6 number with a mean of 8.5. Since the mean is calculated by dividing the sum of the numbers by how many numbers there are, we know that the sum of the numbers have to be 8.5 × 6 = 51.

Subtracting all the known numbers from 51 leaves you with the only possible solution for x: 51 - 11 - 8 - 8 - 7 - 5 = 12.

(No. 5) Start by calculating the total mass of all the spiders. (16 × 175) + (24 × 150) = 6,400. Once again, to calculate the mean, divide the total sum of the numbers by how many numbers there are, in this case you divide the total mass of the spiders by how many spiders there are, leaving you with the average of 6,400 ÷ 40 = 160.

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Answer:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X represent the sample mean for the sample  

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s represent the sample standard deviation

n represent the sample size  

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

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