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nataly862011 [7]
2 years ago
9

Which table shows a proportional relationship?

Mathematics
1 answer:
Aleks04 [339]2 years ago
7 0

Answer:

the table with ' r & s'

Step-by-step explanation:

It's the table with 'r & s' because when you simplify or reduce all the fractions (x/y), you will get them all to return back to 5/1

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Green Leaf Lawn Care had 64 customers under contract at the start of the year. The company's owner expects his new radio adverti
IRINA_888 [86]

Answer:

C. c = 64 + 2w

Step-by-step explanation:

You're starting with 64 customers and you're gaining 2 for each week.

<em>good luck, i hope this helps :)</em>

3 0
3 years ago
Read 2 more answers
Suki split five dog treats equally among her six dogs. Which fraction represents this division.
anzhelika [568]
5 treats divided by six groups of one dog, or in easier terms, five dog treats divided up for 6 dogs. As a fraction, just remove the words except for 5, divided by, and 6, to give you 5/6. Hope this helped.
5 0
3 years ago
What is the slope that passes through the points (-5,0) and (-3,1)
tangare [24]

Answer:

1/2

Step-by-step explanation:

When given two points, we can find the slope by

m = (y2-y1)/(x2-x1)

    = (1-0)/(-3- -5)

     = (1-0) / (-3+5)

      = 1/2

7 0
3 years ago
Read 2 more answers
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
The lateral area of a right cylinder which has a base diameter of 12 cm and a height of 8 cm is?
garik1379 [7]

Answer:

A = 301.59\ cm^2 or A=96\pi\ cm^2

Step-by-step explanation:

The lateral area of a cylinder is calculated by the following formula

A = 2\pi r * h.

Where r is the radius of the right cylinder and h is the height

In this case we know that the diameter d of the cylinder is

d=2r\\\\r=\frac{d}{2}\\\\r=\frac{12}{2}\\\\r=6\ cm

h=8\ cm

Therefore the lateral area is:

A = 2\pi*6 * 8.

A = 96\pi

A = 301.59\ cm^2

8 0
3 years ago
Read 2 more answers
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