Answer:
line1:y=2x+3
Gradient1=2
Let line2 be the line passes through (-4,1)and perpendicular to line1.
Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1
Gradient of line2=-1/2
Equation of line2:y-y1 =m(x-x1)
:y-1 =(-1/2)[x-(-4)]
:(y-1)(-2)=(x+4)
:-2y+2 =x+4
:-2y+2-x-4=0
:-x-2y-2 =0
:x+2y+2 =0
*notes:gradient=m
Answer:
c. domain: {-2, 0, 2}, range: {-1, 1, 3}
Step-by-step explanation:
Given:
There are three points on the graph.
Locate the 
and 
values of the points on the graph.
The points are 
Domain is the set of all possible values. Here, the values are -2, 0 and 2.
So, domain is: {-2, 0, 2}.
Range is set of all possible values. Here, the values are -1, 1 and 3.
So, range is: {-1, 1, 3}
Keep change change [keep the first integer change the opperation and change the integer on your number or fraction ... Rember the answer takes the sign of the larger number .
Answer:
1st one m=0
y= <u>0.49875311x / cm </u>
<u>No horizonal asymptotes</u>
<u>x= 1/2 + 2.005 mcy</u>
<u />
<u>2nd one is </u>
<u>slope 1/2</u>
<u>y intercept (0,2)</u>
<u />
<u>x y</u>
<u>-4 0</u>
<u>0 2</u>
<u />
Step-by-step explanation:
for 2
starting point ay y 2 make a point
then rise over run
go up 1 and to the right 2 and point , then up 1 and to the right 2 and point
there is your graph
Answer:
I tried looking it up, and i found 15 square units. sorry if its wrong :(
Step-by-step explanation:
