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4 years ago

Select the option for “?” That continues the pattern for each question... 3,-6, 12, 4, 20,?

Mathematics

1 answer:

BigorU [14]4 years ago

7 0

Answer: I'm not completely sure

Step-by-step explanation:20

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Help on number four plzzz

vesna_86 [32]

4=3
5=4
6=2
7=5
8=6
9=4
10= 16
16=31
18=36

4 0

4 years ago

Read 2 more answers

The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

Find the distance AB

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

Find the distance BC

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

Find the distance CD

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

Find the distance DE

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

Find the distance AE

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

6 0

3 years ago

Can someone explain INTERQUARTILE RANGE for me, and please give an example. Thank you!

Novosadov [1.4K]

Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!

7 0

3 years ago

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What solution is y=9x+35 y=-8/9x+4/5

Ainat [17]

Answer:

x=-1539/445, y=1724/445. (-1539/445, 1724/445).

Step-by-step explanation:

y=9x+35

y=-8/9x+4/5

-------------------

9x+35=-8/9x+4/5

9x-(-8/9x)=4/5-35

9x+8/9x=4/5-175/5

81/9x+8/9x=-171/5

89/9x=-171/5

x=(-171/5)/(89/9)

x=(-171/5)(9/89)

x=-1539/445

y=9(-1539/445)+35

y=1724/445

6 0

3 years ago

Are 17 heartbeats in 15 seconds and 68 heartbeats in 60 seconds Equivalent

Andre45 [30]

Answer:

1.133.

Step-by-step explanation:

Yes because if you divide 17 by 15 you get about 1.133 and if you divide 68 by 60 you also get about 1.133.

4 0

3 years ago

Read 2 more answers