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Vesna [10]
3 years ago
9

The Columbia Tower in Seattle is 954 feet tall. The Seafirst Tower is T feet tall and stands d feet away from the Columbia Tower

. Find the height of the Seafirst Tower. Give your answer to 2 decimal places.
Mathematics
1 answer:
const2013 [10]3 years ago
6 0
The specification of the problem includes a sketch of the relation between the towers showing two angles.

The sketch shows the segment of the track between the two towers (d), the heights of the two towers (954 feet and T),  and the horizontal angles from the base of each tower to the top of the other tower.

Then you can write two trigonometric ratios.

1) From the triangle formed by the segment that separates the two towers, d, and the height of Sears Tower (T) with horizontal angle 27°:

tan (27°) = T / d => d = T / tan(27°)

2) From the triangle formed by the segment that separates the two towers, d, and the height of Comumbia Tower (954), with horizontal angle 53°

tan(53°) = 954 / d = > d = 954 / tan(53°)

Now you can equal the two equations => 954 / tan(53) = T / tan(27) =>

T = 954 tan(27) / tan (53) =   366.29 feet

Answer: 366.29 feet

 
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Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

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            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

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