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sveticcg [70]
3 years ago
5

Paul travels from Rye to Eston at an average speed of 90km/h. He travels for T hours. Mary makes the same journey at an average

speed of 70km/h. She travels for 1 hour long than Paul. Work out the value of T
Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0
Total distance covered;
For Paul;
sxt=distance
90*t= d
For mary;
s*t=d
70*(t+1)=d
70t+70=d

Since they cover same distance;
70t+70=90t
Putting like terms together;
70=90t-70t
70=20t
t=70/20
t= 3 and 1/2 hours
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Y = -2(x + 5)(x + 1)<br> Set the factor (x + 5) = 0 and solve
Harrizon [31]

Answer: x=-5

Step-by-step explanation:

x+5=0 \implies x=-5

7 0
2 years ago
R is the interior of angle TUV. The measure of RUV=30degrees, the measure of TUV=3x+16, and the measure of TUR=x+10. Find x and
choli [55]

Given

R is the interior of ∠ TUV.

m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.

Find the value of x and the m ∠TUV.

To proof

As given in the question

m ∠TUV=3x+16, and m ∠TUR=x+10

thus

m∠ RUV =  m∠ TUV - m∠ TUR

            = 3x + 16 - x -10

            = 2x + 6

As given

m ∠RUV=30°

compare both the values

we get

30 = 2x + 6

24 = 2x

12 = x

put this value in the m ∠TUV= 3x+16

m ∠TUV= 12× 3 +16

            = 52°

Hence proved


7 0
3 years ago
Find the side length of the equilateral triangle whose area is the square root of 3 cm2
Alla [95]

Here, Given

Area of Equilateral triangle = 3cm2

therefore, we know;

Area of Equilateral triangle =( \sqrt{3}÷4)×a^{2}

so,

3 =( \sqrt{3}÷4)×a^{2}

3÷( \sqrt{3}÷4) = a^{2}

2.63 cm = a .

The area of ​​an equilateral triangle is the area covered by an equilateral triangle on a two-dimensional plane. An equilateral triangle is a triangle with all sides equal and all angles at 60 degrees. The area of ​​the shape is the number of unit squares that fit inside.

Here, "unit" refers to 1, and a unit square is a square with one side. Alternatively, the area of ​​an equilateral triangle is the total amount of space it surrounds in a two-dimensional plane.

Learn more about Area of  triangle  here: brainly.com/question/17335144

#SPJ4

6 0
2 years ago
Given: KLMN is a trapezoid m∠K = 90°, m∠N = 45° LK = LM = 10 Find: KN, Area of KLMN
Ilya [14]
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to A= \frac{LM+KN}{2} *MP= \frac{10+20}{2} *10=150 sq. units.


5 0
3 years ago
Which of the following symbol make(s) the following mathematical statement true?
Arturiano [62]
3 > 1
(4^0 is one)
3 is greater than 4^0
Pretty simple.
3 0
3 years ago
Read 2 more answers
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