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2 years ago

Can someone please please pleaseee helppp

Mathematics

2 answers:

VARVARA [1.3K]2 years ago

5 0

Step-by-step explanation:

Hey there!!!

Here,

The point is, (-3,1).

Using one point formula.

(y-1)= m(x+3)....1st equation.

It has said that it is also perpendicular to the line y = 1/3x + 2 .......2nd equation.

Now, the equation with y = mx + c.

We get slope (m2) = 1/3.

Now,

As per the condition of perpendicular lines,

$m1 \: \times m2 = - 1$

$m1 \times \frac{1}{3} = - 1$

Simplifying them we get,

m1 = -3.

Therefore the slope is -3.

Hope it helps...

uranmaximum [27]2 years ago

4 0

My lucky guess would be 3

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Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3

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Answer:

1) $L(y)=\frac{2}{s^{3}}$

2) $L(y)=\frac{6}{s^{4}}$

Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

Solution :

We know that,

Laplace transforms of $t^n$ is given by,

$L(t^n)=\frac{n!}{s^{n+1}}$

1) $y=t^2$

Laplace of y,

$L(y)=L(t^2)$ here n=2

$L(y)=\frac{2!}{s^{2+1}}$

$L(y)=\frac{2}{s^{3}}$

2) $y=t^3$

Laplace of y,

$L(y)=L(t^3)$ here n=3

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2 years ago

What is the first step needed to solve 3 over 4 multiplied by x minus 3 equals negative 18?

kodGreya [7K]

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3 years ago

App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

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$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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So in this care the width of the picture in 5cm.

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