Answer:
We need a sample of size at least 13.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
90% confidence interval: (0.438, 0.642).
The proportion estimate is the halfway point of these two bounds. So
95% confidence level
So , z is the value of Z that has a pvalue of , so .
Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?
We need a sample of size at least n.
n is found when M = 0.08. So
Rounding up
We need a sample of size at least 13.
Answer:
c(X)=R(X)
125x+18000=215x
18000=215x-125x
18000=90x (divede both sides by 90)
X=200
Answer:
my
Step-by-step explanation:
yo
Answer:
no solution
Step-by-step explanation:
X/3+2=x/3
Subtract x/3 from each side
X/3-x/3+2=x/3-x/3
2 = 0
This is never true so there is no solution