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inna [77]
3 years ago
11

When solving negative one over five (x − 25) = 7, what is the correct sequence of operations?

Mathematics
1 answer:
miv72 [106K]3 years ago
5 0
-\frac{1}{5}(x-25) = 7       multiply 5 to both sides first
-(x-25) = 35                                     then expand the brackets
-x+25=35                                        make x the subject now;
-x=10
x= -10
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In how many year the interest will became equal to the principal is rs.1200 is deposited at the rate of 25% in a bank ​
mrs_skeptik [129]

Given:

Principal = Rs. 1200

Rate of interest = 25%

To find:

The time in which the interest will became equal to the principal.

Solution:

We have,

P=1200

r=\dfrac{25}{100}

r=0.25

If interest is equal to the principal, then

Amount=Principal+Interest

Amount=1200+1200

Amount=2400

The formula for amount is:

A=P\left(1+r)^n

Substituting A=2400, P=1200, r=0.25 in the above formula, we get

2400=1200(1+0.25)^n

\dfrac{2400}{1200}=(1.25)^n

2=(1.25)^n

Taking log on both sides, we get

\log2=\log(1.25)^n

\log2=n\log(1.25)               [\because \log a^b=b\log a]

\dfrac{\log2}{\log(1.25)}=n

n\approx 3.11

Therefore, the interest will became equal to the principal in about 3.11 years.

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2 years ago
Which set best represents the integers?
Blizzard [7]
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3 years ago
Please help me <br> 30 points <br> Show you work
GenaCL600 [577]

Answer:

(a) A translation is a rigid transformation. How does this statement support line s being parallel to line r?

Because ALL of the points of line r move the same distance in the same direction, then the inclination of the line s doesn't change with respect line r.

(b) Write and expression for the slope of line r:

(k-n)/(j-m)

(c) Write and expression for the slope of line s:

(k-n)/(j-m)

(d) Line q is a vertical is a vertical translation of line s 3 units down. P'' is the image of P'. What are the coordinates of P''?

The coordinates of P'' are:

P''=(m,n+ϴ-3)

Step-by-step explanation:

(a) A translation is a rigid transformation. How does this statement support line s being parallel to line r?

Because ALL of the points of line r move the same distance in the same direction, then the inclination of the line s doesn't change with respect line r.


(b) Write and expression for the slope of line r.

Line r goes through the points:

P=(m,n)=(xp,yp)→xp=m, yp=n

Q=(j,k)=(xq,yq)→xq=j, yq=k

Slope of line r is:

mr=(yq-yp)/(xq-xp)

Replacing the coordinates, the expression for the slope of line r is:

mr=(k-n)/(j-m)


(c) Write and expression for the slope of line s.

Line s goes through the points:

P'=(m,n+ϴ)=(xp',yp')→xp'=m, yp'=n+ϴ

Q'=(j,k+ϴ)=(xq',yq')→xq'=j, yq'=k+ϴ

Slope of line s is:

ms=(yq'-yp')/(xq'-xp')

Replacing the coordinates, the expression for the slope of line s is:

ms=[(k+ϴ)-(n+ϴ)]/(j-m)

Eliminating the parentheses in the numerator:

ms=[k+ϴ-n-ϴ]/(j-m)

Simplifyng:

ms=(k-n)/(j-m)


(d) Line q is a vertical is a vertical translation of line s 3 units down. P'' is the image of P'. What are the coordinates of P''?

3 units down, then change only the ordinate y:

P''=(xp',yp'-3)

Replacing xp' and yp':

P''=(m,n+ϴ-3)


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Answer:

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divide both sides by 3                    3x/3 = 144/3

2x + (x + 9) = 153

 

2(48) + (48 + 9) = 153

 

96 + 57 = 153

 

153 = 153

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