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GenaCL600 [577]
2 years ago
14

Find the number of terms in the sequence and find the sum of the sequence: 5+9+13+...+145

Mathematics
1 answer:
SashulF [63]2 years ago
8 0
145-13-9-5 that what your looking for
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How do you determine the number of zeros to Annex in the product of 0.002 + 0.003
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2*10^-3 + 3*10^-3
(2+3)*10^-3
5*10^-3
since the sum of coefficients of the 10^-3 are less than 10, we still have the same number of zeros
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Which of the following is the midpoint formula?
Alika [10]
B is the right answer
5 0
3 years ago
17 students on math team want to raise $483.62 to buy books. They already have raised $218.25.If each student raised the same am
Harlamova29_29 [7]
That answer you are looking for would be $15.61
i hope this helped you with the answer!

7 0
4 years ago
Can someone please help me?
kvasek [131]

now, let's recall the rational root test, check your textbook on it.

so p  = 18 and q = 1

so all possible roots will come from the factors of ±p/q

now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.

recall that, a root will give us a remainder of 0.

let us use +3.


\bf x^4-7x^3+13x^2+3x-18 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{r|rrrrr} 3&1&-7&13&3&18\\ &&3&-12&3&18\\ \cline{1-6} &1&-4&1&6&0 \end{array}\qquad \implies (x-3)(x^3-4x^2+x+6)


well, that one worked... now, using the rational root test, our p = 6, q = 1.

so the factors from ±p/q are ±3, ±2, ±1

let's use 3 again


\bf \begin{array}{r|rrrrr} 3&1&4&1&6\\ &&3&-3&-6\\ \cline{1-5} &1&-1&-2&0 \end{array}\qquad \implies (x-3)(x-3)(x^2-x-2)


and of course, we can factor x²-x-2 to (x-2)(x+1).

(x-3)(x-3)(x-2)(x+1).

7 0
3 years ago
25 miles per hour = how many feet per second
ollegr [7]

Answer:36.67 i think

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
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