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2 years ago

Someone pls help me ill give out brainliest pls don’t answer if you don’t know

Mathematics

1 answer:

Akimi4 [234]2 years ago

5 0

Answer:

$\sqrt{256} \: and \: \sqrt{289}$

Step-by-step explanation:

Explanation:

$\sqrt{256 } = 16 \\ \sqrt{289} \: = 17$

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QUESTION IN PICTURE thx <3

Umnica [9.8K]

Answer:

7 1/9

Step-by-step explanation:

because I know i'm right

6 0

3 years ago

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If 10a+10b=35, what is the average (arithmetic mean) of a and b?

worty [1.4K]

Answer:

1.75

Step-by-step explanation:

If a and b are two numbers, then their arithmetic mean is

$\dfrac{a+b}{2}$

Given:

$10a+10b=35$

Divide this equation by 10:

$a+b=3.5$

Now, divide it by 2:

$\dfrac{a+b}{2}=\dfrac{3.5}{2}\\ \\\dfrac{a+b}{2}=1.75$

6 0

3 years ago

a motorcycle dealer paid a certain price for a motorcycle and marked it up by 1/5 of the price he paid. Later, he sold it for $1

katovenus [111]

Okay so $14,000 is the equivalent of 6/5ths
so divide $14,000 by 6= $2333.3r

you need 5/5
so $2333.3r x 5 = $11666.67
this is the original price

5 0

3 years ago

Helpppp me pleaseeee :}

avanturin [10]

Answer:

The answer is C

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If you know please help me

MrRa [10]

Average rate of change of the function $=\frac{75}{2}$

Solution:

Given function: $f(x)=5(2)^{x}$ from x = 1 to x = 5

Substitute x = 1 and x = 5 in f(x).

$f(1)=5(2)^{1}=10$

$f(5)=5(2)^{5}=160$

Let us find the average rate of change of the function.

Average rate of change

$$=\frac{f(b)-f(a)}{b-a}$

Here a = 1 and b = 5.

$$=\frac{f(5)-f(1)}{5-1}$

Substitute f(5) and f(1).

$$=\frac{160-10}{4}$

$$=\frac{150}{4}$

$$=\frac{75}{2}$

Average rate of change of the function $=\frac{75}{2}$

4 0

3 years ago