Answer:
4/5
Step-by-step explanation:
<u>Given</u>,
Area of the triangle = 1/4 square meters
From the diagram,
Height = 2/5 m
<u>To find</u> : Length of the base
<u>Formula</u> : -
A = bh/2
Here,
A denotes Area
b denotes Base
h denotes Height
A = 1/4
h = 2/5
A = bh/2
Cross multiply,
A * 2 = bh
2A = bh
2 * (1/4) = b * (2/5)
(1 * 2)/4 = (b * 2)/5
2/4 = 2b/5
1/2 = 2b/5
Cross multiply,
1 * 5 = 2 * 2b
5 = 4b
b = 4/5 meters
Hence,
The length of the base is 4/5 meters.
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
The first one is your answer because if you plug into the cal it shows the x and y table and it shows that the first one is correct.
Answer:(7,3)
Step-by-step explanation:
So am I supposed to divide or multiply