1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex777 [14]
2 years ago
12

Quick algebra 1 question for 10 points!

Mathematics
2 answers:
andreyandreev [35.5K]2 years ago
3 0

Answer:

\textsf{D. }x\leq-2

Step-by-step explanation:

<u>Given inequality:</u> 3(x+2)\leq5(-2-x)

Step 1: Distribute 3 and 5 through the parentheses.

\implies 3(x)+3(2)\leq5(-2)+5(-x)

\implies 3x+6\leq-10-5x

Step 2: Subtract 6 from both sides.

\implies 3x+6-6\leq-10-6-5x

\implies 3x\leq-16-5x

Step 3: Add 5x to both sides.

\implies 3x+5x\leq-16-5x+5x

\implies 8x\leq-16

Step 4: Divide both sides by 8.

\implies \dfrac{8x}{8}\leq\dfrac{-16}{8}

\implies x\leq-2

nadezda [96]2 years ago
3 0

Answer:

x ≤ -2

Step-by-step explanation:

3(x + 2) ≤ 5(-2 - x)

Distribute on both sides.

3x + 6 ≤ -10 - 5x

Add 5x to both sides.

8x + 6 ≤ -10

Subtract 6 from both sides.

8x ≤ -16

Divide both sides by 8.

x ≤ -2

You might be interested in
Need some help on this question please:(​
xxTIMURxx [149]

Answer:

B

Step-by-step explanation:

sorry if its wrong

5 0
3 years ago
Can someone help me with this? PLs i'm so confused!
barxatty [35]
1. E. sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

2. L. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

3. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}

4. Y. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

5. W. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

6. tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}

7. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

8. W. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}

9. I. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

10. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

11. E. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}

12. I. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

13. U. sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}

14. I. cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}

15. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}

16. R. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}

17. M. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}

18. N. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}

19. L. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}

20. H. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}

21. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}

22. O. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

23. O. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

24. N. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1
7 0
3 years ago
Which relation is a function?
Leno4ka [110]

Answer:

The bottom left one

Step-by-step explanation:

They are the only graph that has one output for each x value

3 0
1 year ago
The midpoint of sm is (5,-11). One endpoint is S(3,5). What are the coordinates of endpoint M?
Nitella [24]
The coordinates of the midpoint if the endpoints are (x₁,y₁) and (x₂,y₂):
(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

One endpoint is (3,5), the midpoint is (5,-11). The other endpoint is (x,y).

\frac{3+x}{2}=5 \ \ \ \ \ \ \ \ |\times 2 \\&#10;3+x=10 \ \ \ \ \  |-3 \\&#10;x=7 \\ \\&#10;\frac{5+y}{2}=-11 \ \ \ \ \ |\times 2 \\&#10;5+y=-22 \ \ \  |-5 \\&#10;y=-27

The coordinates of endpoint M are (7,-27).
3 0
3 years ago
You are mailing a gift box that is 17 inches by 14 inches by 10 inches. You want to put it in a larger box and surround it with
MatroZZZ [7]

Answer:

2040 cubic inches

Explanation:

5 0
2 years ago
Other questions:
  • I need some help with my math :(
    12·1 answer
  • (9 divided by 3) + 4 (6 minus 7)<br> –7<br> –1<br> 7<br> 20<br> HELP ME PLZ
    10·1 answer
  • The Cougars football team took possession of the ball on the 23-yard line moving toward the 50-yard line. On the first play from
    13·1 answer
  • F(x)=x^2 what is g(x)
    7·1 answer
  • The graph below shows the transformation from triangle 1 to triangle 2.
    10·2 answers
  • A printer is printing photos. For every 10 photos, the printer takes 2 minutes.
    14·1 answer
  • one renting a movie he started the movie at 11:43 p.m. and it was 2 hours for 45 minutes long when did the movie End​
    14·1 answer
  • Find measure of arc HJ. *
    6·2 answers
  • A fast food store had two size fries
    6·1 answer
  • 6 quarters + 5 dimes + 3 Nickels + 4 Pennys
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!