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cricket20 [7]
3 years ago
12

Consider the line y=9x-5.

Mathematics
1 answer:
igomit [66]3 years ago
6 0
Y = 9x - 5...the slope here is 9...a parallel line will have the same slope.

y = mx + b
slope(m) = 9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = 9(5) + b
-4 = 45 + b
-4 - 45 = b
-49 = b
so ur parallel line is : y = 9x - 49

y = 9x - 5...slope is 9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/9.

y = mx + b
slope(m) = -1/9
(5,-4)...x = 5 and y = -4
now we sub and solve for b, the y int
-4 = -1/9(5) + b
-4 = -5/9 + b
-4 + 5/9 = b
-36/9 + 5/9 = b
- 31/9 = b

so ur perpendicular line is : y = -1/9x - 31/9

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The equation y + 6 = one-third (X minus 9) is written in point-slope form. What is the equation written in slope-intercept form?
stiks02 [169]

The equation written in slope-intercept form is y = (1/3)x -9

<h3>What is a linear Equation ?</h3>

A linear equation is that which can be represented in the form of y =mx +c , m is the slope and c is the intercept.

The given equation is

y+6 = 1/3(x-9)

To determine the slope and the intercept this equation needs to be solved

y+6 = (1/3)x - 3

y = (1/3)x -9

Therefore this is the slope intercept format , here

the slope = 1/3

intercept = -9

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4 0
1 year ago
Determine the points of intersection of the line y=2x+5 and the circle x²+y²=36
Vladimir79 [104]

The two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

<h3>How to find the points of intersection?</h3>

Here we want to solve the system of equations:

y = 2x + 5

x² + y² = 36

To solve this, we need to replace the first equation into the second one:

x² + (2x + 5)² = 36

Now we can solve this for x:

x² + 4x² + 10x + 25 = 36

5x² + 10x - 11 = 0

This is a quadratic equation, to solve it we use the general formula:

x = \frac{-10 \pm \sqrt{10^2 - 4*5*(-11)} }{2*5} \\\\x = \frac{-10 \pm 17.9 }{10}

So we have two solutions for x:

x = (-10 - 17.9)/10 = -2.79

x = (-10 + 17.9)/10 = 0.79

To get the y-values of the solutions, we evaluate the linear equation in these values of x:

y = 2*(-2.79) + 5 = -0.58

y = 2*( 0.79) + 5 = 6.58

Then the two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

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5 0
2 years ago
Write the equation of the lines resented below in slope-intercept form
scoray [572]

Slope intercept form: y = mx + b

mx = slope

b = y-intercept

We know the y intercept is 0, so nothing will be written there.

To find the slope of this line, we can use the slope formula.

\frac{y.2 - y.1}{x.2 - x.1} = m

We'll use the points (1, 0) and (3, 1) to find the slope.

Now we can just plug these values into the equation to find the slope.

1 - 0 / 3 - 1

1 / 2

The slope of the line is 1/2, or 0.5.

The slope-intercept form of this line can be written as:

y = 0.5x

6 0
3 years ago
Write the slope intercept form of a line that passes<br> through (3, -2) and is 1 to y = x + 3.
zhuklara [117]

Answer:12

Step-by-step explanation:

8 0
4 years ago
-2x - 10 =15 help me plzzzz
Dima020 [189]

Answer:

x = -12.5

Step-by-step explanation:

Solve :  -2x - 10 =15

-2x - 10 = 15

-2x = 15 + 10

-2x = 25

x = -25/2

x = -12.5

6 0
3 years ago
Read 2 more answers
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