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3 years ago

Are points A,E, and I coplanar?

Mathematics

1 answer:

amm18123 years ago

8 0

Answer:

Yes.

Step-by-step explanation:

Any three points will always be coplanar.

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How to solve this question? Please help me

Maurinko [17]

Answer:

≈ 82 feet

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to calculate distance (d)

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

Here the hypotenuse is the distance (d) between the 2 poles, hence

d² = 80² + 45² = 6400 + 2025 = 8425 ( take the square root of both sides )

d = $\sqrt{8425}$ ≈ 82 feet ( to the nearest foot )

8 0

3 years ago

How do you draw a line for this

m_a_m_a [10]

I'd do a little more than 77minutes for the 6and 7for if you could have it on 77and but you could have it in your head

8 0

3 years ago

Read 2 more answers

I am running out of points!! Please help me!!

IceJOKER [234]

ANSWER

$165.6 \degree$

EXPLANATION

The measure of arc AC corresponds to 22% + 24%=46%

The complete angle of the circle is 360°.

Therefore the measure of arc AC is

$= \frac{46}{100} \times 360$

This simplifies to

$165.6 \degree$

The correct answer is A.

7 0

3 years ago

Solve for t.

Drupady [299]

C .............................

7 0

3 years ago

A paint can has a radius of 4 inches and a height of 15 inches. What is the volume of the paint can? Round to the nearest tenth.

Archy [21]

Answer:

$V=753.6\ \text{inches}^3$

Step-by-step explanation:

Given that,

Radius of a paint can, r = 4 inches

Height of a paint can, h = 15 inches

We need to find the volume of the paint can. We know that the shape of a paint can is in the form of cylinder such that the volume of cylinder is given by :

$V=\pi r^2h$

Substituting all the values we get

$V=3.14\times (4)^2\times 15\\\\V=753.6\ \text{inches}^3$

So, the volume of the paint can is 753.6 cubic inches.

5 0

3 years ago