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3 years ago

Which statement is not always true?

1 answer:

4 0

Statement #3: The product of two irrational numbers is not always irrational.

If you multiply √3 and 1/√3, both irrational numbers that are inverses of each other, you end up getting 1, which is rational.

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motorcycle cover 210 kilometre distance with 5 l of petrol how many kilometre does it cover with 8 litre of petrol? how much pet

Likurg_2 [28]

Answer:

A: 336 km

B: 14 L

Step-by-step explanation:

Use a proportion

210 km / 5 L = x / 8L Cross multiply

8*210 = 5 x

1680 = 5x

x = 1680 / 5

x = 336 km

===============

210 /5 = 588/x Cross multiply

210x = 588 * 5

210x = 2940 Divide by 210

x = 2940/210

x = 14 L

3 0

3 years ago

Is (5,1) a solution to the equation 2x-y=11? Explain

grigory [225]

This is simple. Coordinate form is (x,y) so you would just plug in your values.

2(5)-(1)=11

10-1 does not equal 11, so no it is not a solution.

7 0

3 years ago

Read 2 more answers

Which expression represents the series 1+5+25+125+625

tankabanditka [31]

$a_n=5^n$
where n starts at 0.

$a_n=5^{(n-1)}$
where n starts at 1.

7 0

3 years ago

I suck at math so I'm gunna ask a bunch of questions on this work

Nastasia [14]

It would be c plz mark me brainliest

3 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago