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Brilliant_brown [7]
3 years ago
15

Anyone know this. Pls help now.

Mathematics
1 answer:
Annette [7]3 years ago
8 0

Scale factor basically means multiplying.

New coordinates: -12, 0

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The slope is 3/2 or 1.5
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the combined age of april and laura is 23 years. laura's age is two years more than half of april's age. what is laura's age
Kipish [7]

Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = \frac{x}{2}

2 years more than half of April's age = \frac{x}{2}+2

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$\Rightarrow \ \ x+(\frac{x}{2}+2) =23

$\Rightarrow \ \ x+\frac{x}{2}+2 =23

$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

$\Rightarrow \ \ \frac{x\times2}{1\times2}+\frac{x}{2}+\frac{2\times2}{1\times2} =23

$\Rightarrow \ \ \frac{2x}{2}+\frac{x}{2}+\frac{4}{2} =23

Denominators are same, now add the fractions.

$\Rightarrow \ \ \frac{2x+x+4}{2} =23

Do cross multiplication.

$\Rightarrow \ \ 2x+x+4=23\times2

$\Rightarrow \ \ 3x=46-4

$\Rightarrow \ \ 3x=42

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Laura's age = \frac{14}{2}+2

                    = 7 + 2

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Hence Laura's age is 9 years.

8 0
3 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

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Romashka [77]
Hi.
your answer is c: 6.38 but the actual answer of your question is 11.
hope this helps!!!
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