Answer:
Option D. h(2) = 16
Step-by-step explanation:
Verify each statement
case A) h(8) = 21
The statement is false
Because
we know that
h(8)=19 -----> given value
and
If h(8) = 21 then f(x) is not a function
case B) h(13) = 18
The statement is false
Because x=13 not belong to the domain of the function
case C) h(-3) = -1
The statement is false
Because
x=-3 belong to the domain
but
h(-3)=-1 not belong to the range of the function
case D) h(2) = 16
The statement could be true
Because
x=2 ----> belong to the domain of the function
h(2)=16 ----> belong to the range of the function
Answer:
aa
Step-by-step explanation:
15/14 1 and 1/14 is the answer
I'm assuming the function is f(x) = (2x+8)/(x^2+5x+6). If so, make sure to use parenthesis to indicate that you're dividing all of "2x+8" over all of "x^2+5x+6" as one big fraction. Otherwise, things are ambiguous and it leads to confusion.
Side Note: x^2 means "x squared"
Factor the numerator: 2x+8 = 2(x+4)
Factor the denominator: x^2+5x+6 = (x+2)(x+3)
There are no common factors between the numerator and denominator. So there is nothing to cancel out.
Recall that you cannot divide by zero. Something like 1/0 is undefined.
We need to find the x values that cause the denominator to be zero.
Set the denominator equal to zero and solve for x
x^2+5x+6 = 0
(x+2)(x+3) = 0
x+2 = 0 or x+3 = 0
x = -2 or x = -3
The x values x = -2 or x = -3 will lead to the denominator being zero. This means that the vertical asymptotes are x = -2 or x = -3 as shown by the blue dashed vertical lines in the attached image.
Answer:
y= 1/2 X + 3/4
Step-by-step explanation:
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