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Anarel [89]
3 years ago
9

The radius of circle L is 22 cm.

Mathematics
2 answers:
den301095 [7]3 years ago
7 0

Answer:

Option B 44\ cm

Step-by-step explanation:

we know that

The radius of the circle is half the diameter

Let

r-----> the radius of the circle

D----> the diameter of the circle

we have

r=22\ cm

r=\frac{D}{2}

Solve for the diameter

D=2r

substitute the value of r

D=2(22)=44\ cm

IrinaK [193]3 years ago
3 0
Diameter = 2*(radius)
The radius is half of the diameter, so if you were given the radius and need to find the diameter, multiply the radius by two. If you were given the diameter and need to find the radius, divide the dimaeter by two
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Step-by-step explanation:

The base is less than 1.

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1. If AD = 25, then BC =<br> 2. If AB = 30, then DC =
Aleonysh [2.5K]

Answer:

1. BC=25

2. DC=30

Step-by-step explanation:

In a parallelogram, pairs of opposite sides are always equal. The side opposite of AD is BC, so if AD=25, BC=25. Likewise, if side AB=30, side DC=30. Of course, this is assuming the shape is a parallelogram. If it is not, there is no way of determining the side lengths.

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3 years ago
7. Find the length of AB<br> please answer will mark brainelist :)
Julli [10]

Answer:

A) 17 m  B) 20.8 m

Step-by-step explanation:

I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11

26-11 = 15

I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)

AB is the hypotenuse

We can use the pythagorean theorem  to find length AB (a^2 + b^2 = c^2)

a and b is the legs which is 8 and 15

8^2 + 15^2 = AB^2

64 + 225 = AB^2

289 = AB^2

√289 = AB (to undo a square, you use square roots)

√289 = 17

AB = 17 m

Now we need to find the hypotenuse of AC

the same thing, we did for problem A, use the pythagorean theorem

17^2 + 12^2 = AC^2

289 + 144 = AC^2

433 = AC^2

√433 = AC

√433 is <em>about </em>20.808...

round to the tenth as stated in the directions

AC = 20.8 m

7 0
3 years ago
a hall 100 feet in length is to be designed as a whispering gallery. If the foci are located 25 feet from the​ center, how high
ki77a [65]

Answer:

how high will the ceiling be at the center? ≈43.3 ft above the center

Step-by-step explanation:

standard form of equation for an ellipse with horizontal major axis and center at the origin:

x^2/a^2+y^2/b^2=1, a>b

for given problem:

a=50

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c^2=a^2-b^2

b^2=a^2-c^2=2500-625=1875

b=√1875≈43.3 ft

≈43.3 ft above the center

8 0
3 years ago
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