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2 years ago

14

Solve to find the value of n

1 answer:

Shalnov [3]2 years ago

5 0

Answer:

is C

Step-by-step explanation:

why are we doing it at school and i did it and it's many solutions

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givi [52]

Answer:

i thin correct answer is b

8 0

2 years ago

One of the roots of the equation 5x2−36x+t=0 is five times as big as the other root. Find the value of t.

Bas_tet [7]

Answer:

t = 36

Step-by-step explanation:

If one of the roots is "a", the equation can be factored as ...

(5x -a)(x -a) = 0

5x^2 -6ax +a^2 = 0

Comparing terms to the given equation, we see that ...

-6ax = -36x

a = 6 . . . . . . . . divide by -6

Then ...

a^2 = t

36 = t . . . . . . . substitute 6 for a

_____

The roots are 6 and 6/5.

4 0

3 years ago

Jenny works in a picture framing shop. She has a function f(x) equals X +2 that find the size of a square frame, given a picture

Iteru [2.4K]

Given:

The function for size of a square frame is

$f(x)=x+2$

where, x is the side length of the picture.

The function for the price in dollars for the frame is

$p(x)=3x$

To find:

The single function for the price of a picture with an edge length of x.

Solution:

We know that, for a picture with an edge length of x.

Size of a square frame = f(x)

Price in dollars for the frame = p(x)

Single function for the price of a picture with an edge length of x is

$(p\circ f)(x)=p(f(x))$

$(p\circ f)(x)=p(x+2)$ $[\because f(x)=x+2]$

$(p\circ f)(x)=3(x+2)$ $[\because p(x)=3x]$

Let the name of this function is c(x). So,

$c(x)=3(x+2)$

Therefore, the required function is $c(x)=3(x+2)$ .

8 0

3 years ago

X and y vary inversely and x=50 when y=5 find y when x=10 what is k?

Kisachek [45]

Answer:

Part A)

1) $k=250$

2) $y=25$

Part B)

1) $k=7$

2) $y=84$

Step-by-step explanation:

Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

step 1

<u>Find the value of k</u>

x=50 when y=5

substitute the values

$y*x=k$ ------> $5*50=k$ -----> $k=250$

The equation is equal to

$y*x=250$ or $y=250/x$

step 2

<u>Find y when x=10</u>

substitute the value of x in the equation and solve for y

$y*(10)=250$

$y=250/10=25$

Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

step 1

<u>Find the value of k</u>

x=6 when y=42

substitute the values

$y/x=k$ ------> $42/6=k$ -----> $k=7$

The equation is equal to

$y/x=7$ or $y=7x$

step 2

<u>Find y when x=12</u>

substitute the value of x in the equation and solve for y

$y=7(12)=84$

5 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago