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sdas [7]
3 years ago
11

What gose first x axis or y axis when you write it

Mathematics
1 answer:
alexira [117]3 years ago
7 0

Answer:

the x axis goes first

Step-by-step explanation:

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There were 436 tickets purchased for a major league baseball game. The general admission tickets cost ​$6.50 and the upper reser
Nataly [62]

Answer:

How many general admission tickets were​ purchased? __<u>136</u>__

How many upper reserved tickets we purchased? _<u>300</u>_

Step-by-step explanation:

Let the number of general tickets = g.

Let the number of reserved tickets = r.

6.5g + 8r = 3284

g + r = 436

     6.5g + 8r = 3284

(+)   -8g + -8r = -3488

--------------------------------

     -1.5g         = -204

g = 136

g + r = 436

136 + r = 436

r = 300

Answer:

How many general admission tickets were​ purchased? __<u>136</u>__

How many upper reserved tickets we purchased? _<u>300</u>_

8 0
3 years ago
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In triangle ABC, (angle A) is a right angle and (m angle B) = 45deg.
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We can use the ratios for special triangles (see the attachment below). We'll be using the 45-45-90 triangle. We notice that side BC is equal to x \sqrt{2}, and side AC (x using the special right triangle) is equal to 16. We can therefore say that side BC is equal to 16 \sqrt{2} ft

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4 0
4 years ago
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Georgia’s scores in six subjects are 89, 75, 92, 68, 78, 75, and 80. If she finds a single value that summarizes all the values
posledela
It would be mean. The mean is the average that is you are looking for, since she wants a summerization of all the values in the data set. To find the mean (average) add all the numbers and then divide by the amount of numbers.
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3 years ago
Estimate the quotients 3.53/51 =
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An accurate estimate is anywhere from 0.06 to 0.07. The exact answer is 0.06921568627.
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4 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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