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3 years ago

Please answer this correctly

Mathematics

1 answer:

Alenkasestr [34]3 years ago

7 0

Answer:

5/12

Step-by-step explanation:

The probability of rolling a number greater than 1 is 5/6, because 5 numbers on a 6-sided dice are greater than 1.

The probability of rolling an even number is 3/6, because 3 numbers on a 6-sided dice are even numbers.

$5/6 \times 3/6$

$=15/36$

$=5/12$

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The sum of 6 consecutive even numbers is 270.What is the second number in this sequence?

Finger [1]

Answer: 42

Step-by-step explanation:

Let the six consecutive even numbers be x , x+2 , x+4 ,x+6 ,x+8 ,x+10.

Then According to the question , we have

$x+(x+2)+(x+4)+(x+6)+(x+8)+(x+10)=270\\\\\Rightarrow\ x+x+2+x+4+x+6+x+8+x+10=270\\\\\Rightarrow\6x+30=270\\\\\Rightarrow\ 6x=270-30\\\\\Rightarrow\ 6x=240\\\\\Rightarrow\ x=40$

Now, the second number from the above six consecutive even numbers is x+2.

Substitute the value of x in it, we get

The second number in this sequence = $x+2=40+2=42$

3 0

3 years ago

Read 2 more answers

Jason poured 1 gallon 1 quart of water into an empty 2-gallon bucket. How much more water can be added to reach the bucket's 2-g

Romashka [77]

Answer: 3 quart

Step-by-step explanation:

Given

Jason poured 1 gallon 1 quart of water into an empty 2 gallon bucket

1 gallon can be written as 4 quart

So, 2 gallon can be written as 8 quart

Subtract 1 gallon 1 quart(5 quart) from 2 gallon(8 quart) to get the volume added

$\Rightarrow 8-5\\\Rightarrow 3\ \text{quart}$

So, 3 quart of water must be added to reach 2 gallon capacity.

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3 years ago

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DanielleElmas [232]

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2 years ago

A gumball machine has just been filled with 50 black, 150 white, 100 red and 100 yellow gum balls that have been thoroughly mixe

Andrew [12]

<span>Exactly 33/532, or about 6.2% This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball. There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red. Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133. So the combined probability of both of the 1st 2 gumballs being red is 1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>

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3 years ago

Solve for the indicated variable: ⅖(z + 1) = y for z.

sweet [91]

Answer:

z = 5/2y -1

Step-by-step explanation:

We observe that z has ...