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stellarik [79]
3 years ago
10

Which of the following choices represents a balanced chemical equation? A. Ca3(PO4)2 + 6SiO2 → P4O10 + 3CaSiO3 B. 2Ca3(PO4)2 + 6

SiO2 → P4O10 + 6CaSiO3 C. 2Ca3(PO4)2 + 3SiO2 → 2P4O10 + 2CaSiO3 D. 3Ca3(PO4)2 + 2SiO2 → P4O10 + 4CaSiO3
Chemistry
1 answer:
Arturiano [62]3 years ago
6 0

 the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

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LightWave. Lightwave forms the most important example of a transverse wave!
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How many gallon are there in 85.00 L?
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22.46

Explanation:

.There are 3.79 liters in one gallon

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How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the densit
denpristay [2]

Balance the equation first: 

2 Fe+6 HNO3→2 Fe(NO3)3+3H2

Then calculate mass of Iron :

4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe

Now use Stoichiometry:

371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3

Convert moles of nitric acid to grams

19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3



7 0
3 years ago
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What can you say about the strength of the intermolecular forces in neon and argon based on the critical points of Ne and Ar? (c
algol13

Explanation:

Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.

It is known that gas phase of neon occurs at 50 K. As the boiling point of Ar is more than the boiling point of neon which means that there is strong intermolecular force of attraction between argon molecules as compared to neon molecules.

This is also because argon is larger in size. As a result, induced dipole-induced dipole forces leads to more strength in Ar as compared to Ne.

8 0
3 years ago
How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?
Nata [24]

Answer:

\boxed{\text{53 g }}

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                 142.04  

             2NaOH + … ⟶ Na₂SO₄ + …  

n/mol:      0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces \boxed{\text{53 g }} of Na₂SO₄.

4 0
3 years ago
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