The energy that was released by the candy is calculates using the below formula
Q=Mc delta T
Q= heat energy
m= mass (500g)
C= specific heat capacity) = 4.18 j/g/c
delta t =change in temperature = 25- 21 = 4 c
Q= 500 g x 4.18 j/g/c x 4c = 8360 j
Answer: True
Air is a mixture of many things; it's not just Oxygen, but Hydrogen, Carbon, and Nitrogen as well are made up of air. Fun fact: Nitrogen is actually more abundant in air
Answer:
We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.
Explanation:
- Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.
<em>(MV) before dilution = (MV) after dilution.</em>
M before dilution = 1.0 M, V before dilution = ??? mL.
M after dilution = 0.2 M, V after dilution = 100 mL.
<em>∴ V before dilution = (MV) after dilution / M before dilution </em>= (0.2 M)(100 mL) / (1.0 M) = <em>20.0 mL.</em>
<em>So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.</em>
Answer:
As the electrostatically charged object is to be placed in the field of charged particles it will be attracted to those who would be of oppositely charged and repelled by the same charged particles. phenomenon of like charges repel and opposite charges attract each other will be carried out and no deflection will be shown by the charge towards the neutral charge.
Given:
Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M
Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution
Assume: 50:50 ratio of fluoride ions and HF
12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-
5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles
Assume: Volume additive
Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M
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