Answer:
Monosaccharides are simple sugars with a basic formula Cⁿ (H2O)ⁿ. They are classified according to the number of carbon atoms they contain: tetroses (4), pentoses (5) and hexoses (6). There are also mosaccharides with 3 carbon atoms, for example the Dihydroxyacetone.
Explanation:
Monosaccharides have to be aldehydes (-CHO) or ketones (-COO) with more than one alcohol function, which will be located in different carbons.
Answer:
A. Integumentary system
Explanation:
The integumentary system consists of the skin,hair and nail. This system consists of the largest organ in the body. The skin helps in protection against pathogens by shielding the internal body system from external objects.
The skin also helps in Vitamin D production through sunlight.
It also helps to prevent dehydration through regulation of water loss.
Last option: Preserve an ecosystem
• The establishment of a bird reservation is a way to preserve an ecosystem because reservation provides suitable environment to organism. A healthy ecosystem means large number of biodiversity.
Answer:
Option A, an unconstitutional restriction of speech
Explanation:
Please see the attachment
Answer:
The order must be K2→K1, since the permanently active K1 allele (K1a) is able to propagate the signal onward even when its upstream activator K2 is inactive (K2i). The reverse order would have resulted in a failure to signal (K1a→K2i), since the permanently active K1a kinase would be attempting to activate a dead K2i kinase.
Explanation:
- You characterize a double mutant cell that contains K2 with type I mutation and K1 with type II
mutation.
- You observe that the response is seen even when no extracellular signal is provided.
- In the normal pathway, i f K1 activat es K2, we expect t his combinat ion of two m utants to show no response with or without ext racell ular signal. This is because no matt er how active K1 i s, it would be unable to act ivate a mutant K2 that i s an activit y defi cient. If we reverse the order, K2 activating K1, the above observati on is valid. Therefore, in the normal signaling pathway, K2 activates K1.
