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Vsevolod [243]
3 years ago
12

Between which two consecutive integers

\sqrt{72} " alt=" \sqrt{72} " align="absmiddle" class="latex-formula">
lies

​
Mathematics
1 answer:
True [87]3 years ago
7 0

Answer:

8 and 9

Step-by-step explanation:

Find the 2 perfect square either side of 72 , that is

64 < 72 < 81 , then

\sqrt{64} < \sqrt{72} < \sqrt{81}

8 < \sqrt{72} < 9

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When a number is decreased by 40 %40% of​ itself, the result is 6060. what is the​ number?
WITCHER [35]
X - 0.40x = 60
0.60x = 60
x = 60 / 0.60
x = 100 <== ur number
8 0
3 years ago
10. Solve the system of equations 3y + 2z = 12 and y – z = 9. A. y = 6, z = –3 B. y = 24, z = 15 C. y = 6, z = 15 D. y = –6, z =
zhannawk [14.2K]
3y + 2z = 12
Now you just try every answer until you get the right one.
A) y=6 z=-3
3×6 + 2×(-3) =18 -6=12
This is CORRECT
B) y=24 z=15
3×24 + 2×15= 72 + 30 =102
This is INCORRECT
C) y=6 z=15
3×6 + 2×15=18+30=48
This is INCORRECT
D)y=-6 z=15
3×(-6) + 2×15 = -18 + 30 = 12
This is CORRECT
So the correct answers are A and D
6 0
3 years ago
redo question 18 above with the same amount of deposit and the same interest rate, but with the interest compounded quarterly. h
yanalaym [24]
There are no given figures. I'll just show what the difference is. Let us assume the following
Principal = 10,000
interest rate = 12%
term = 4 years

Simple Interest = Principal * interest rate * term
S.I = 10,000 * 12% * 4 years
S.I = 4,800

Total value at the end of 4 yrs = 10,000 + 4,800 = 14,800

Compounded Interest. Compounded quarterly.
A = P(1 + r/n)^n*t
A = 10,000 (1 + 12%/4)^4*4
A = 10,000 (1.03)^16
A = 10,000 (1.60)
A = 16,000 value after 4 years.
5 0
3 years ago
I need help pleaseeeeee nowplease
marysya [2.9K]
This is a pretty complex problem
6 0
3 years ago
Which expressions show the expanded form for 200.06? Choose all answers that are correct. A. 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/
saveliy_v [14]

Answer:

Therefore,

Correct options are

A)  2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

D) 2 × 100 + 6 × 1/100

Step-by-step explanation:

Given:

Number is

200.06

For option A)

2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

= 200 + 0 + 0 + 0.06

= 200.06

Which is CORRECT.

For option B)

2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000

= 200 + 0 + 0 + 0.006

=200.006

Which is INCORRECT.

For option C)

2 × 100 + 6 × 1/10

= 200 + 0.6

= 200.6

Which is INCORRECT.

For option D)

2 × 100 + 6 × 1/100

= 200 + 0.06

= 200.06

Which is CORRECT.

Therefore,

Correct options are

A)  2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

D) 2 × 100 + 6 × 1/100

5 0
3 years ago
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