The answer is:
It’s equivalent to 30+5y
Answer: C
Step-by-step explanation:
For this problem, we need to know the standard form of a sine function and the meaning of each part.
Standard form: ![y=asin[b(x-h)]+k](https://tex.z-dn.net/?f=y%3Dasin%5Bb%28x-h%29%5D%2Bk)
a=amplitude
b=period
h=phase shift
k=vertical replacement/shifting
Now that we know the standard form and the components, we know that we can forget about k and plug in 0 for h. This would leave us with ![y=asin[b(x)]](https://tex.z-dn.net/?f=y%3Dasin%5Bb%28x%29%5D)
. We know that the amplitude is 2, therefore, a=2. To find the period, you divide 2π by the given period. 
, therefore, b=1/2.
[plug in a=2]
![y=2sin[b(x)]](https://tex.z-dn.net/?f=y%3D2sin%5Bb%28x%29%5D)
[plug in b=1/2]
Therefore, C is the correct answer.
Anwer:3.537m
STEP BY STEP EXPLANATIOND:using SOH CAH TOA
First find the opposite
Represent the opposite with x
Tan 33° =x\10
x=10Tan 33°
x=6.494
To find m
Sin 33°=m\6.494 Sin 33°
m=3.5368
m=3.537meteres
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Answer: 21p^2 + 3qp
Explanation:
To find the area of the triangle you have to do LxHx1/2
Length = 7p+q
Height = 6p
(7p+q)*6p*1/2 = 21p^2+3qp
I hope this helped!
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- Zack Slocum
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Substitute 6 - 2x for y in the first equation
3x - (6 - 2x) = 4
5x - 6 = 4
5x = 10
x = 2
Plug 5 for x in either equations (I'll use the second equation)
y = 6 - 2 * 2
y = 6 - 4
y = 2
(2,2) is the solution.
