Solve system using eliminations<br> 2x+4y=22<br> 2x-2y=-8

Rachel and 5 friends were going to the movies.Each ticket cost $8 and they bought 4 popcorns at $6.25 a piece and then each pers

larisa86 [58]

6 persons * $8= $48
4 popcorns * $6.25= $25
6 persons * $2.75= $16.5 (drinks)

$48+$25+$16.5= $89.50 total

7 0

4 years ago

TRYNNA FINISH THIS .. ILL MARK THE BRAINLIEST

Ann [662]

Answer:

A

Step-by-step explanation:

1 pound = 16 ounces

so pounds are multiplied by 16 to convert to ounces

3 0

3 years ago

Read 2 more answers

A fee of $12.50 is deducted each month from Aubryn’s bank account. She currently has a balance of $75.00 in her account. She mus

xxTIMURxx [149]

Current balance - 12 months a year times the monthly fee

=75-12(12.50)
=75-150
=-75

She will have negative $75 so she will be below zero.

4 0

4 years ago

In the diagram shown, line m is parallel to line n . Justine says that ∠3 ∠ 3 and ∠7 ∠ 7 are supplementary angles. Is she correc

agasfer [191]

The correct answer is C.

Because by looking at the diagram you can see that angles 7 and 8 are intersected

6 0

3 years ago

in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok

grandymaker [24]

Answer:

$z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869$

$p_v =2*P(Z>1.869)=0.0616$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

$\hat p=0.849$ estimated proportion of adults were no longer smoking after one month

$p_o=0.80$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:

Null hypothesis: $p=0.8$

Alternative hypothesis: $p \neq 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z>1.869)=0.0616$

If we compare the p value obtained and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .

6 0

3 years ago

Solve system using eliminations 2x+4y=22 2x-2y=-8