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lorasvet [3.4K]

3 years ago

6

Tickets for a basketball game cost $2 for students and $5 for adults. The number of students was 3 less than 10 times the number

of adults. The total amount of money from ticket sales was $619. How many of each ticket were sold?

2 answers:

34kurt3 years ago

6 0

2x+5y=619
x=10y-3
________
2(10y-3) +5y=619
20y-6+5y=619
25y=619+6
25y=625
y=625/25
y=25
x=10*25-3
x=250-3
x=247

Evgesh-ka [11]3 years ago

3 0

Answer:

The no. of adult's tickets sold is 25.

The no. of adult's tickets sold is 247

Step-by-step explanation:

Given :

Tickets for a basketball game cost $2 for students and $5 for adults.

The number of students was 3 less than 10 times the number of adults.

The total amount of money from ticket sales was $619.

To Find : No. of each ticket were sold

Solution :

Let x be the no. of the student's tickets sold

Let y be the no. of adult's tickets sold

Since we are given that The number of students was 3 less than 10 times the number of adults.

⇒ x = 10y -3 --(A)

Now cost of 1 student's ticket is $2

Thus, cost of x student's ticket is $2x

Now cost of 1 adult's ticket is $5

Thus,cost of y adult's ticket is $5y

Since we are given that the total amount of money from ticket sales was $619.

⇒2x +5y =619 ---(B)

Solving equation A and B by substitution method :

putting value of x from (A) in (B)

We get :

⇒2( 10y -3) +5y =619

⇒20y-6+5y= 619

⇒25y = 625

⇒y = 625/25

⇒y=25

Thus, the no. of adult's tickets sold is 25.

Putting value of y in equation A to get value of x .

⇒x = 10(25) -3

⇒x = 247

Thus the no. of adult's tickets sold is 247

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