Question

Find the area of a triangle with sides of length 10 and 24 and included angle 20°. (round your answer to one decimal place.)

Answer 1

$\text {Area of triangle = } \dfrac{1}{2} \text{ab} \sin \text{c}$

$\text {Area of triangle = } \dfrac{1}{2} (10)(24) \sin (20 \textdegree)$

$\text {Area of triangle = } 41.0 \text{units}^2$