Given:
ABC is an isosceles triangle in which AC =BC.
D and E are points on BC and AC such that CE=CD.
To prove:
Triangle ACD and BCE are congruent.
Solution:
In triangle ACD and BCE,
(Given)

(Common angle)
(Given)

In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.
(SAS congruence postulate)
Hence proved.
Answer: x² + 4x - 32
Step-by-step explanation: So to multiply these two binomials together, let's use the F.O.I.L. method.
Remember, F.O.I.L. stands for First, Outter, Inner, Last.
This is because we start with the product of the first terms which is x², then we add the product of the outer terms which is 8x, then we add the middle terms which is -4x, and then we add the product of the last terms which is -32.
So we have x² + 8x + -4x + -32.
Combining the like terms 8x + -4x, our final answer is x² + 4x - 32.
Answer:
y ≈ 0.7
Step-by-step explanation:
locate
on the x-axis, move up the vertical line until meeting the graph then the horizontal reading gives y ≈ 0.7
Answer:
m∠WXY+m∠ZXY=m∠WXZ
Step-by-step explanation:
You don't know the angles to be congruent (equal measures), complementary (measures add to 90 deg), or supplementary (measures add to 180 deg); all you know is that they are adjacent, so the sum of the measures of the two smaller angles equals the measure of the larger outer angle.
Answer: m∠WXY+m∠ZXY=m∠WXZ
Answer:
The vertex is (5, 12)
Step-by-step explanation:
The vertex, from vertex form, is (h,k).
Vertex form is a(x - h)² + k
= 2(x - 5)² + 12
So h = 5, k = 12
The vertex is (5, 12).
I hope this helped!