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stepan [7]
3 years ago
15

A researcher collated data on Americans’ leisure time activities. She found the mean number of hours spent watching television e

ach weekday to be 2.7 hours with a standard deviation of 0.2 hours. Jonathan believes that his football team buddies watch less television than the average American. He gathered data from 40 football teammates and found the mean to be 2.3. Which of the following are the correct null and alternate hypotheses?
Mathematics
2 answers:
irakobra [83]3 years ago
7 0
The answer is: 

(null hypothesis) u=2.7; Ha(alt hypothesis): u<2.7 
trapecia [35]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that a researcher collected data on Americans leisure activities.  Mean number of hours spent watching TV X is having mean 2.7 and std deviation 0.2.

Sample size = 40

Sample mean = 2.3

To test the hypothesis

Null hypothesis should be mu =2.7

and alternate hypothesis should be mu <2.7

We compare sample mean with population mean.

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The value of X in this question is 46                 
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3 years ago
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-2.1b +5.3= b -- 3.1b + 5.3<br><br> does is have one solution or infinitely many solutions ? Why ?
pychu [463]

Answer: infinitely many solutions.

Step-by-step explanation:

Ok, our equation is:

-2.1*b + 5.3 = b - 3.1*b + 5.3

now, simplifyng the right side, we have:

b - 3.1*b + 5.3 = (1 - 3.1)*b + 5.3 = -2.1*b + 5.3

Then our initial expression is:

-2.1*b + 5.3 = -2.1*b + 5.3

So in both sides of the equality we have the exact same thing, so this is a trivial equality.

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6 0
3 years ago
Need math help (last one wouldn't let me upload pic)
Scrat [10]

Answer:

\text{Area of the figure}=54\text{ unit}^2

Step-by-step explanation:

Please find the attachment.

Let us divide our given image in several parts and then we will find area of different parts.

First of all let us find the area of our red rectangle with side lengths 6 units and 7 units.

\text{Area of rectangle}=\text{Length*Width}

\text{Area of red rectangle part}=6\text{ units}\times 7\text{ units}

\text{Area of red rectangle part}=42\text{ units}^2

Now let us find area of yellow triangle on the top of red rectangle. We can see that base of triangle is 6 units and height is 1 unit.

\text{Area of triangle}=\frac{1}{2}\times \text{Base*Height}

\text{Area of triangle}=\frac{1}{2}\times \text{6 units *1 unit}

\text{Area of triangle}=3\text{ unit}^2

Let us find the area of green triangle.

\text{Area of green triangle}=\frac{1}{2}\times \text{3 units *2 units}

\text{Area of green triangle}=3\text{ unit}^2

Now we will find the area of blue triangle, whose base is 6 units and height is 2 units.

\text{Area of blue triangle}=\frac{1}{2}\times \text{6 units *2 units}

\text{Area of blue triangle}=6\text{ units}^2

Let us add all these areas to find the area of our figure.

\text{Area of the figure}=42\text{ units}^2+3\text{ unit}^2+3\text{ unit}^2+6\text{ unit}^2

\text{Area of the figure}=(42+3+3+6)\text{ unit}^2

\text{Area of the figure}=54\text{ unit}^2

Therefore, area of our given figure is 54 square units.  

3 0
3 years ago
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Answer:

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scoundrel [369]
Its going to be 6.75

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8 0
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