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Tanzania [10]
3 years ago
9

Could someone help me with this

Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

option b is correct answee

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The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

7 0
3 years ago
Is there any app which helps solve pure maths questions?​
allochka39001 [22]

Answer:

math a app good luck with the question

4 0
2 years ago
6a What is the Answer?
zavuch27 [327]

We have been provided a diagram which tells us that Patti drew vertical line segments from two points to the line in her scatter plot. The first point she selected was dwarf crocodile. The second point she selected was for an Indian Gharial crocodile.

We can see that dwarf crocodile's bite force is closer to line of best fit than Indian Gharial crocodile. Indian Gharial crocodile seems to be an outlier for our data set.

Therefore, Patti's line have resulted in a predicted bite force that was closer to actual bite force for the dwarf crocodile.

6 0
3 years ago
Find the sum of nth term of the series 1+3/2+5/2^2+7/2^3+.......
ioda

Answer:

an = (1 + 2·(n - 1))/2^(n - 1) = 2^(1 - n)·(2·n - 1)

sn = 6 - 2·0.5^n·(2·n + 3)


6 0
4 years ago
Find x round to the nearest tenth
jeka94
<h3>Answer: angle X = 70.5 degrees</h3>

=================================================

Work Shown:

Law of Cosines

c^2 = a^2 + b^2 - 2ab*cos(C)

22^2 = 20^2 + 18^2 - 2*20*18*cos(X)

484 = 724 - 720*cos(X)

484 + 720*cos(X) = 724

720*cos(X) = 724 - 484

720*cos(X) = 240

cos(X) = 240/720

cos(X) = 1/3

X = arccos(1/3)

X = 70.528779

X = 70.5

Make sure your calculator is in degree mode.

7 0
3 years ago
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