we are given
sum of three consecutive numbers are 303
Let's assume
first term is a-d
second term is a
third term is a+d
now, we can add them
so, middle term is 101
so, largest term will be greater than middle term
so, largest term must be greater than 101
so, option-A........Answer
3(5+7) is the problem you are looking at. To figure it out, you can use properties. On the right side of the equals sign, it shows a property you can use to do the problem. In this case, they are distributing.
Answer:
n=-3
m=1
Step-by-step explanation:
get m by itself then plug it in for the other m and solve, then solve for n.
w = 3(2a + b) - 4
First, add 4 to both sides:
w (+4) = 3(2a + b) - 4 (+4)
w + 4 = 3(2a + b)
Next, divide 3 from both sides:
(w + 4)/3 = (3(2a + b))/3
(w + 4)/3 = 2a + b
Next, subtract b from both sides:
((w + 4)/3) - b = 2a + b (-b)
(w + 4)/3 - b = 2a
Finally, divide 2 from both sides:
((w + 4)/3 - b)/2 = (2a)/2
a = (((w + 4)/3) - b)/2
a = (((w + 4)/3) - b)/2 is your answer.
~
