All categories

3 years ago

Look at the unit circle shown below.

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

7 0

Answer:

The correct option is A.

Step-by-step explanation:

Draw a perpendicular form point P on x-axis.

Radius of unit circle is 1 . It means in triangle OPA

Hypotenuse = OP = 1 units

Adjacent= OA = x

Perpendicular = PA = y

In a circle angled triangle,

$\cos \theta = \frac{adjacent}{hypotenuse}$

In triangle OPA,

$\cos \theta = \frac{x}{1}$

$\cos \theta =x$

The x-coordinate of P corresponds to cosθ.

The period of a unit circle is 2π.

Therefore, the correct option is A.

maksim [4K]3 years ago

4 0

Answer:

A is true.

Step-by-step explanation:

Cos θ = adjacent / hypotenuse = x/1 = x.

Cosθ has a period pf 2π.

You might be interested in

The midpoint of the line segment at (1,7) and (5,5) is A) (3,6) B) (2,6) C) (3,1) D) (2,1)

hammer [34]

Answer:

A) (3,6)

Step-by-step explanation:

Let M be the midpoint of the line segment at (1,7) and (5,5). Then:

$\mathsf{M\left(\dfrac{1+5}{2},\dfrac{7+5}{2}\right)}=\\=\mathsf{M\left(\dfrac{6}{2},\dfrac{12}{2}\right)}=\\=\mathsf{M\left(3,\,6\right)}$

5 0

4 years ago

Solve for x. . Please wait for photo to load.

VladimirAG [237]

C because 83-2 is 81 and the square root of 81 is 9 because 9 times 9 is 81 and C is 81 so C is correct

3 0

3 years ago

Please help!! I've attached a picture of the problem

BARSIC [14]

Answer: BC=8 units

Step-by-step explanation:

So in this figure, this triangle, that is a parallelogram named DFCE , and one of their property three yeti you add learn you learned is that a parallelogram has like rectangle two sides per two that are parallel and have the same measure ( but you can also use the little lines that show who is the same as who ) in this one you can write an equality: CE=FD=4. Then there is the same two lines on the EB segment so EB=4 . Then we can write that BC= BE + EC

BC= 4+4

BC= 8 units

I’m not English so I tried explaining as simple as possible sorry if you didn’t understand :/

3 0

3 years ago

A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc

lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0

3 years ago

The Pacific Ring of Fire is an area where the Pacific Tectonic Plate encounters other tectonic plates. Which types of encounters

zhannawk [14.2K]

A) convergent boundaries
This is where plates collide.

3 0

3 years ago