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omeli [17]
3 years ago
5

determine an equation of a line in standard form that is perpendicular lo the line 2y = -x + 3 and passes through the point (4,

5).​
Mathematics
1 answer:
Nataliya [291]3 years ago
4 0
First, i put the equation in y=mx+b by dividing 2, since its 2y. since it’s perpendicular we’re talking about you switch the sides (opposite reciprocals). the rest should be self explanatory.

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How do I solve this equation: -5/6b + 3/4 = 1/2b - 2/3 ?
Gre4nikov [31]
First get like things on the same side:
-5/6b - 1/2b= -2/3 - 3/4

Then find equivalent fractions to make the equation easier to solve.
-5/6b - 3/6b= -8/12 - 9/12

Then just add things together and solve.
-8/6b= -17/12
-8b= 6(-17/12)
-8b= -17/2
b= (-17/2)/-8
b= 17/16

You can then plug the answer back into the original question to make sure it is the correct answer.
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3 years ago
A line passes through the points (1, 4) and (3, –4). which is the slope of the line?
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3 years ago
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4 0
3 years ago
Read 2 more answers
One zero of f(x)=x^3-2x^2-5x+6 is 1 what are other zeros of the function
elena-s [515]

Answer:

The other zeros are -2 and 3.

Step-by-step explanation:

As 1 is a zero then (x - 1) is a factor so we divide:

x - 1 )x^3-2x^2-5x+6(x^2-x-6

        x^3-x^2

              -x^2-5x

              -x^2+x

                      -6x+6    

                      -6x+6

                       ...........

x^2 - x - 6 = 0

(x - 3)(x + 2)

x = -2, 3.

7 0
3 years ago
Read 2 more answers
I don’t understand. and someone please help?
givi [52]

Solution:

<u>Note that:</u>

  • 6x + 26 = 92 (Vertically opposite angle)
  • 92 + 92 + z + z = 360

<u>Finding x.</u>

  • 6x + 26 = 92
  • => 6x = 92 - 26
  • => 6x = 66
  • => x = 11

<u>Finding z.</u>

  • 92 + 92 + z + z = 360
  • => 184 + 2z = 360
  • => 2z = 360 - 184
  • => 2z = 176
  • => z = 176/2 = 88
3 0
2 years ago
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