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den301095 [7]
3 years ago
8

A rental hall has 60 tables.

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:for the second question/First question that is unsolved it's

350

for the second unsolved question its200

for the third unsolved one its  550

Step-by-step explanation:

The first one is wrong 55%=35

45%=25

35x10=350

25x8=200

add it =550

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Ellen went to the hardware store and purchased 7 pounds of size 1 screws for $63.96. How much did she pay for 1 pound? Ellen sai
Nataly [62]

Answer:

Yes, if you divide the $63.96 by the 7 pounds you get $9.13

Step-by-step explanation:

8 0
4 years ago
There are 527 pencils,646 erasers and 748 sharpeners. These are to be put in separate packets containing the same number of item
sp2606 [1]

Answer:

  • 31 pencils
  • 38 erasers
  • 44 sharpeners

Step-by-step explanation:

The number of packets is the greatest common divisor of the given numbers of pencils, erasers, and sharpeners.

It can be helpful to look at the differences between these numbers:

  748 -646 = 102

  646 -527 = 119

The difference of these differences is 17, suggesting that will be the number of packets possible.

  527 = 17 × 31

  646 = 17 × 38

  748 = 17 × 44

The numbers 31, 38, and 44 are relatively prime (31 is actually prime), so there can be no greater number of packets than 17.

There will be 31 pencils, 38 erasers, and 44 sharpeners in each of the 17 packets.

_____

We may have worked the wrong problem. The way it is worded, the <em>maximum</em> number of items in each packet will be 527 pencils, 646 erasers, and 748 sharpeners in one (1) packet. The <em>minimum</em> number of items in each packet will be the number that corresponds to the maximum number of packets. Since 17 is the maximum number of packets, each packet's contents are as described above.

17 is the only common factor of the given numbers, so will be the number of groups (plural) into which the items can be arranged.

6 0
3 years ago
HELP MEEE PLEASEE SHOOW UR WOORRKK
stiks02 [169]

Answer:

b

Step-by-step explanation:

2(k-5)+3k=k+6

step 1 distribute the 2 to whats in the parenthesis

2k-10+3k=k+6

step 2 combine any like terms if there are any

5k-10=k+6

step 3 add 10 to each side

5k=k+16

step 4 subtract 1k from each side

4k=16

step 5 divide each side by 4

k=4

6 0
3 years ago
In ΔTUV, the measure of ∠V=90°, the measure of ∠U=55°, and VT = 82 feet. Find the length of TU to the nearest tenth of a foot.
Degger [83]

<u>Given</u>:

Given that TUV is a right triangle with measure of ∠V=90°

The measure of ∠U = 55°, and the length of VT is 82 feet.

We need to determine the length of TU.

<u>Length of TU:</u>

The length of TU can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

where \theta=55^{\circ}, opp = VT and hyp = TU

Thus, we have;

sin \ 55^{\circ}=\frac{VT}{TU}

Substituting the values, we have;

sin \ 55^{\circ}=\frac{82}{TU}

Simplifying, we have;

TU=\frac{82}{sin \ 55^{\circ}}

TU=\frac{82}{0.819}

TU=100.1

Thus, the length of TU is 100.1 feet.

8 0
3 years ago
Find factors of g(x)=2x^3+3x^2-23x-12 when (2x+1) is a factor
Sliva [168]

Answer:

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 (((2 • (x3)) -  3x2) -  23x) +  12

STEP  

2

:

Equation at the end of step

2

:

 ((2x3 -  3x2) -  23x) +  12

STEP

3

:

Checking for a perfect cube

3.1    2x3-3x2-23x+12  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  2x3-3x2-23x+12  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -23x+12  

Group 2:  2x3-3x2  

Pull out from each group separately :

Group 1:   (-23x+12) • (1) = (23x-12) • (-1)

Group 2:   (2x-3) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

8 0
3 years ago
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